Answer: The formula of (a + b)3 is a3 + b3 + 3ab (a + b).
The formula of (a3 + b3) is (a + b) (a2 – ab + b2).
The formula of (a – b)3 is a3 – b3 – 3ab (a-b).
The formula of (a3 – b3) is (a – b) (a2 + ab + b2).
The above equations can be proved true by assuming a value for ‘a’ as well as ‘b’. Let us take ‘a’ = 1 and ‘b’ = 2.
To prove (a + b)3 is a3 + b3 + 3ab (a + b), put a =1 and b = 2 in this equation.
First we will solve LHS = (a + b)3
= (1+2)3
= (3)3
= 27.
Now, take the RHS = a3 + b3 + 3ab (a + b)
= (1)3 + (2)3 + 3 x 1 x 2 (1+2)
= 1 + 8 + 6 (3)
= 1+ 8 + 18
= 27.
Here LHS = RHS, hence the equation is correct.
By following the same steps, other equations can also be verified.
Summary:
a3 b3 formula
The formula of (a + b)3, (a3 + b3), (a – b)3, and (a3 – b3) with example have been presented in this post. Check the details above.
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