  # The Product of Two Consecutive Positive Integers is 306. Find the Integers.

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Updated on: September 25th, 2023 17 and 18 are two consecutive positive integers whose product is 306. To calculate this solution, we will consider two numbers a and a+1, as both numbers are consecutive. By using algebraic expressions, we will solve this question to derive our answer. Positive integers are known by another name which is natural numbers and refer to numbers that have a value more than zero.

Table of content ## Two Consecutive Positive Integers with Product 306

To find the two consecutive positive integers whose product equals 306, we will first assume the two integers to be a and a + 1, as we already know both numbers are consecutive. Keeping this in mind, we will solve the question in the following manner.

We already know that the product of a and (a + 1) is 306. So, we will write it in the following way –
⇒a(a + 1) = 306

Now, to solve this equation, we will follow the below-mentioned steps –

a² + a – 306 = 0

= a² + 18a – 17a – 306 = 0

=a(a + 18) – 17(a + 18) = 0

=(a + 18)(a – 17) = 0

=a = 17 and -18

Now, we have the values of a and a+1 which are –

a = 17 and (a +1) = 18

Thus, the two positive integers that are consecutive with product 306 are 17 and 18.

## What are Positive Integers?

Positive integers refer to numbers that are bigger in value than 0. On a number line, such numbers are represented on the right side. The numbers on the left side are known as negative integers. Another name for positive integers is natural numbers. Examples of positive integers include 1,2,3,4,5,6,7,8,11,14, etc.

Summary:

## The Product of Two Consecutive Positive Integers is 306. Find the Integers

The two consecutive positive integers with product 3016 are 17 and 18. To get our answer, we will denote our two numbers as a and a+1. Positive integers refer to numbers that are greater than zero and are also called natural numbers.

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