  # An electron moving with a velocity of 5×104ms-1 enters into a uniform electric field and acquires a uniform acceleration of 104ms-2 in the direction of its initial motion (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity. (ii) How much distance the electron would cover in this time?

By BYJU'S Exam Prep

Updated on: September 25th, 2023 (i) The time in which the electron would acquire a velocity double of its initial velocity is 5s.

(ii) The distance the electron would cover in this time is 37.5×104m.

Step 1: Given that

Acceleration acquired by the electron, a=104ms-2

Initial velocity of the electron, u=5×104ms-1

Step 2: Consider the formulae to calculate Distance covered

We can infer the following using the three motion equations:

Distance covered, s=ut+1/2at2,

Where u is the starting speed, t is the travel time, and an is the body’s acceleration.

We also know that,

time, ∆t=v-ua∵a=∆v∆t

Step 3: Now we have to find the time required to double the initial velocity

We require that the final velocity be twice as fast as the initial velocity, thus, v=2u=2×5×104=105ms-1.

We require that the final velocity be twice as fast as the initial velocity is, t=10×104-5×104/104=5s

Step 4: Now we have to find the distance covered

The distance travelled is determined by the first equation by

s=5×104×5+1/2×104×52

On simplifying we get

s=37.5×104m

Therefore,

Five seconds are needed to double the initial velocity.

distance travelled while double the initial velocity is 37.5×104m.

Summary:-

## An Electron moving with a velocity of 5×104ms-1 enters into a uniform electric field and acquires a uniform acceleration of 104ms-2 in the direction of its initial motion (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity.(ii) How much distance the electron would cover in this time?

An electron moving with a velocity of 5×104ms-1 enters into a uniform electric field and acquires a uniform acceleration of 104ms-2 in the direction of its initial motion

(i) The time in which the electron would acquire a velocity double of its initial velocity is 5s.

(ii) The distance the electron would cover in this time is 37.5×104m.

Related Questions:-

POPULAR EXAMS
SSC and Bank
Other Exams GradeStack Learning Pvt. Ltd.Windsor IT Park, Tower - A, 2nd Floor, Sector 125, Noida, Uttar Pradesh 201303 help@byjusexamprep.com