# Basic Concepts & Short Tricks of Fictitious Symbol questions

By Rahul Chadha|Updated : November 21st, 2019

The Reasoning section of every competitive exam includes questions from the topic “Mathematical Operators/ Fictitious Symbols”. Here, we are uploading different types of questions which will surely help you in the upcoming Railways & SSC ExamsThis topic deals with the questions on the basics of fundamental operations — addition, subtraction, multiplication and division. Sometimes, the questions involving these operations are set using artificial symbols. The candidate has to substitute the real signs and solve the questions accordingly to get the answer.

## Basic Concepts & Short Tricks of Fictitious Symbol questions

Different types of questions covered in this chapter are as follows

• Symbol Substitution
• Balancing the Equation
• Interchange of Signs and Numbers
• Trick Based Mathematical Operations

Note:- While solving a mathematical expression, proceed according to the rule BODMASi.e., Brackets, Of, Division, Multiplication, Addition, Subtraction.

Example:

(36 -12) ÷4 + 6 + 2 x 3 = 24 ÷ 4 + 6 + 2 x 3 (Solving Bracket)

= 6 + 6 + 2 x 3 (Solving Division)

= 6+6+6  (Solving Multiplication)

= 18     (Solving Addition)

### Type 1: Symbol Substitution

In this type of question, a candidate is provided with the substitutes for various mathematical symbols followed by a question involving calculation of an expression or choosing the correct/ incorrect equation. The candidate is required to put in the real signs in the given equation and then solve the questions as required.

Ex 1: if ‘×’ means ‘-’, ‘÷’ means ‘+’, + means ‘×’, then 18 × 5 ÷ 5 +6 is equal to

1. 58
2. 49
3. 43
4. 37

Solution: (c)

Change of symbols according to the question,

? = 18 × 5 ÷ 5 + 6 = 18 – 5 + 5 × 6

= 18 – 5 + 30 = (13 + 30) = 43

### Type 2: Balancing the Equation

In this type of questions, the signs in one of the alternatives are required to fill up the blank spaces in order to balance the given equation

Ex: Choose the correct option in order to balance the following equation.

24 6  12  16 = 0

1. - , + and +
2. ÷, + and ÷
3. -, - and -
4. ÷, + and –

Solution: (d)

From Option (d)

Hence, option (d) is correct.

### Type 3: Interchange of Signs and Numbers

In this type of questions, the given equation becomes correct and fully balanced when either two signs of the equation or both the numbers and the signs of the equation are interchanged. The candidate is required to find the correct pair of signs and numbers from the given options.

Ex: Choose the correct interchange option in order to make the given equation correct

10 – 2 +9 × 2 ÷ 4 = 19

1. ÷,+,x and -
2. -,+,x and +
3. ÷, ÷,÷ and ×
4. ×,÷,× and ÷

Solution: (a)

Let us check the options one by one

From option (a),

As options (a) gives us the correct answer. Hence, there is no need to check other options

### Type 4: Trick Based Mathematical Operations

The questions are based on simple mathematical operations that do not follow a universal rule. These questions can be based on several different patterns.

Ex: If 9 × 5 × 2 = 529 and 4 × 7 × 2 = 724, then 3 × 9 × 8 = ?

1. 983
2. 839
3. 938
4. 893

Solution: (a)

= 983

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write a comment

Pradeep SainiMay 15, 2019

ty sir

Nalin Kanta BarikMay 19, 2019

Thank you sir

RAJESH KUMAR YADAVNov 21, 2019

Thank you @Rahul Chadha Ji👍

Rashmi GangoliyaNov 29, 2019

Ssc

Vikash SheelaDec 12, 2019

Thanks for gaeid..bro

Santosh kumarDec 30, 2019

Nice work sir ji and thanks for providing this.

Ajay GuptaJan 9, 2020

Thanks

Pratima GuptaJan 12, 2020

Practice quiz hindi me kyu nhi aa rha h??
Thank you sir

Debabrata DasFeb 6, 2020

Yes

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