Answer: (A)- πd3/16
The polar modulus of shaft section is equal to πd3/16.
Solution: Torsional section modulus or polar modulus of shaft section is equal to the ratio of polar moment of inertia to the radius of the shaft. It is denoted by Zp.
For a solid shaft, Zp= J/r= (πd4/32)(D/2) = πd3/16
Where,
- J- Polar moment of inertia.
- D- Diameter of the shaft.
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