# Availability and Irreversibility Study Notes for GATE & Mechanical Engineering Exams

By Vijay Pratap Singh|Updated : January 4th, 2022
Availability and Irreversibility study notes are vital in any Mechanical Engineering exam. The Availability and Irreversibility study material is of utmost use if you are preparing for the GATE exam. In this article, we have provided to you the notes for the Mechanical exam that will help you to get clarity of the concepts that you have studied so far.

The topic-wise study notes that are given here are helpful for the preparation of various upcoming engineering exams such as GATE MEIES ESE MEBARC MEISRO MESSC JE and other state engineering service examinations. This article comprises of the important study notes on the "Availability and Irreversibility" topic of the "Thermodynamics " subject.

The Available Energy (AE) is also known as exergy and the Unavailable Energy (UAE) is anergy. The energy which cannot be utilised for doing useful work is called unavailable energy.

## Availability

When a system is subjected to a process from its original state to dead state the maximum amount of useful work that can be achieved under ideal conditions is known as available energy or availability of the system. Wmax = AE = Qxy – T0(Sy-Sx)

Unavailable Energy:  UAE = T0(Sy-Sx)

where, Sx and Sy are the entropy at x and y, respectively.

The Available Energy (AE) is also known as exergy and Unavailable Energy (UAE) as energy. The energy which cannot be utilised for doing useful work is called unavailable energy. Irreversibility is equivalent to energy destroyed, hence also known as energy destruction consider the example given below. ## Decrease in availability when Heat is transferred through finite temperature Difference Consider a reversible heat engine operating between T1 and T0.

Q1 = T1. Δs

W = AE= (T1 – T0)Δs

Let us now consider heat Q1 is transferred through a finite temperature difference.

Q1 = T1 Δs = T’1 . Δs’

Δs’ > Δs

Q2 = T0 Δs → Initial UAE

Q’2 = T0 Δs’ ⇒ Afterward UAE

Q’2 > Q2

W’ =Q’1 – Q’2

W’ = T’1 Δs’ – T0Δs’

W’ = (T’1 – T0) Δs’

W = (T1 – T0) Δs

Hence increase in UAE and the shaded portion represents an increase in UAE.

## Second Law Efficiency

Second law efficiency is the ratio of the exergy recovered to the exergy spent. OR It is the ratio of actual work produced to the max work produced under reversible conditions. Consider the case of heat engine.  The second law efficiency is a measure of the performance of a device relative to its performance under reversible conditions.

## Exergy: Closed System

Consider a piston-cylinder device that contains a fluid of mass m at temperature T and pressure P. The system is then allowed to undergo a differential change of state during which volume changes by dV and heat is transferred from the system to surroundings. For change of exergy from state 1 to state 2.

Φ1 = (E1 – E0) + P0(V1 – V0) – T0(S1 – S0)

Φ2 = (E2 – E0) + P0(V2 – V0) – T0(S2 – S0)

Φ1 – ϕ2 = Energy at state 1 – Energy at state 2

Φ1 – ϕ2 = (E1 – E2) + P0 (V1 – V2) – T0(S1 – S2)

## Exergy : Open System

A flowing fluid has an additional form of energy, called flow energy, which is the energy needed to maintain flow in a Pipe.

Wflow = PV Exergy associated with system is

Φflowing fluid = ϕnon flow fluid + ϕflow

Φflowing fluid = (E1 – E0) + P0(V1 – V0) – T0(S1 – S0) +P1V1 – P0V0

Φflowing= U1- U0 + (KE)1 - (KE)0 + (PE)1 – (PE)0 + P1V1 – P0V0 – T0 (S1 – S0)

Φflowing fluid = (U1 + P1V1) – (U0 + P0V0) – T0(S1 – S0) + (KE)1 – (KE)0 + (PE)1 – (PE)0

Φflowing = (H1 – H0) – T0 (S1 – S0) + (KE)1 – (KE)0 + (PE)1 – (PE)2

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