A Hockey Ball of Mass 200 G Travelling at 10 Ms-1 is Struck by a Hockey Stick So as to Return It Along Its Original Path With a Velocity at 5 Ms-1. Calculate the Change of Momentum That Occurred in the Motion of the Hockey Ball by the Force Applied by the Hockey Stick

By BYJU'S Exam Prep

Updated on: September 25th, 2023

A hockey ball of mass 200 g travelling at 10 ms^-1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 ms^-1. The change of momentum that occurred in the motion of the hockey ball by the force applied by the hockey stick is 3 Ns.

Step 1: It is given that

Initial velocity of the ball (u) = 10 ms^-1

Mass of ball (m) = 200 g = 0.2 kg

Final velocity of the ball (v) = 5 ms^-1

Step 2: Now we should determine the change in momentum

Change in momentum ΔP = Final momentum – Initial momentum

ΔP = m (v – u)

ΔP = 0.2 x (-5 – 10)

ΔP = -3 kgms^-1

ΔP = 3 Ns

Table of content

1. A Hockey Ball of Mass 200 G Travelling at 10 Ms-1 is Struck by a Hockey Stick So as to Return It Along Its Original Path With a Velocity at 5 Ms-1. Calculate the Change of Momentum That Occurred in the Motion of the Hockey Ball by the Force Applied by the Hockey Stick

Momentum

Momentum is a vector quantity since it is an object’s propensity to move. It is determined by multiplying the object’s mass by its velocity. The total momentum of the objects before and after the interaction is the same if neither is being affected by any external forces. The conservation of momentum refers to this relationship under the fundamental law of physics.

The occurrence of collision and explosion can be explained using this fundamental tenet of physics. The formula for momentum is provided by,

Momentum (P) = mass (m) x velocity (v)

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