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The Brakes Applied by a Car Produces an Acceleration of 6 M/s2 in Opposite Direction of Motion. If the Car Takes 2 Sec to Stop After the Application of Brakes. Calculate Distance During This Time
By BYJU'S Exam Prep
Updated on: September 25th, 2023
The brakes applied by a car produces an acceleration of 6 m/s2 in opposite direction of motion. If the car takes 2 sec to stop after the application of brakes. The distance travelled during this time is 12 m.
Step 1 – It is given that
Time t = 2s
Acceleration a = 6 m/s2
Final velocity v = 0 m/s
Consider u as the initial velocity
Step 2 – Calculate the distance
We know that the third equation of motion,
v2 – u2 = 2as
Substituting the values we get
02 – u2 = 2 (-6) s
On simplifying we get
12s = u2 …. (1)
Assume the distance as s
Using the first equation of the motion we can write as
v = u + at
0 = u + (-6) 2
On simplifying we get
u = 12 m/s
Substituting u in equation (1)
We get
12s = 122
s = 12 m
Therefore, the distance travelled is 12 m
Equations of Motion Applications
- We can now employ the three equations of motion to solve kinematic issues as a result of having seen them all. Simply identifying all of the parameters will allow us to select the proper equation and solve for the necessary parameter.
- Calculating optical characteristics also makes use of the equations of motion.
Summary:-
The Brakes Applied by a Car Produces an Acceleration of 6 M/s2 in Opposite Direction of Motion. If the Car Takes 2 Sec to Stop After the Application of Brakes. Calculate Distance During This Time
A car’s brakes cause a 6 m/s2 acceleration in the opposing direction of motion. if the car stops after applying the brakes after 2 seconds. This time period covered a distance of 12 m. The equation of motion can be used to calculate the optical characteristics
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