How do you prepare a 1M HCl solution, which has a specific gravity of 1.18? The HCl solution has 35% purity. Calculate the volume required to prepare the solution

By BYJU'S Exam Prep

Updated on: September 25th, 2023

The volume required to prepare 1M HCl solution, which has a specific gravity of 1.18 is 88 mL

Step 1: Mass of solution to create the 35% pure

Assume we need to prepare 1L of 1 mol L^-1 HCl.

The molarity of the HCl solution is 1M, or the number of moles of solute per litre of solution.

In other words, 1M HCl equals 1L of water and 1 mole of HCl.

1 g is mass of hydrogen.

35.5g make up mass of chlorine.

So, molar mass of HCl = 35.5 + 1 = 36.5 g

The HCl solution is 35% pure, which means 35g of HCl are present.

In order to achieve 35% purity, the solution’s mass will be.

36.5 g x 100g/35g = 104.2g

Table of content

Step 2: Quantity needed

A substance’s specific gravity is determined by dividing its mass by the mass of an equivalent volume of water at the same pressure and temperature.

Accordingly, specific gravity is defined as mass per unit volume (V) of a material divided by V’s volume.

This equation can be changed to reveal the volume needed to get the 1M HCl solution’s specific gravity of 1.18:

A volume’s size is calculated by multiplying its mass by its specific gravity.

= 104.2/1.18

= 88 mL

As a result, 88 mL are needed to make 1 M HCl solution, which has a specific gravity of 1.18.

Summary:-

To create 1M HCl solution, which has a specific gravity of 1.18, 88 mL is needed.

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