Geometric Design of The Track
Different gauges
Safe speed on curves Based on Martins Formula
(a) For Transition curve
(i) For B, G & M.G
V=4.35√5-67 where, V is in kmph.
(ii) For N,G V = 3.65√R-6 For V is km/hr.
(b) For non-Transition curve
V=0.80 × speed calculated in (a)
(c) For high speed Trains V=4.58√R
Safe speed Based on Super Elevation
(a) For Transition curves
The above two formula based on the assumption that G = 1750 mm for B.G
G = 1057 mm for N.G
And Where, e = super elevation.
Where, v= speed in km/hr
R = Radius of curve in ‘mm’
Ca = Actual cant in ‘mm’
Cd = Cant deficiency in ‘mm’
Speed from the Length of Transition Curve
(a) For speed upto 100 km/hr.
(min. of two is adopted)
Where, L = Length of transition curve based on rate of change of cant as 38 mm/sec. for speed upto 100 km/hr & 55 mm/sec for speed upto 100 km/hr & 55 mm/sec for high speeds.
Ca = Actual cant in ‘mm’
Cd = Cant deficiency in ‘mm’
(b) For high speed trains (speed>100km/hr)
Either,
Minimum of the two is adopted.
Radius & Degree of curve
if one chain length = 30 m.
if one chain length = 20 m
Where, R = Radius
D = Degree of curve
Virsine of Curve (V)
Grade compensation
For B.G → 0.04% per degree of curve
M.G → 0.03% per degree of curve
M.G → 0.02% per degree of curve
Super Elevation (cant)(e)
Where, Vav = Average speed or equilibrium speed.
Equilibrium speed or Average Speed (Vav)
(a) when maximum sanctioned speed>50km/hr.
(b) When sanctioned speed <50 km/hr
(c) Weighted Average Method
Where, n1,n2,n3… etc. are number of trains running at speeds v1,v2,v3… etc.
Maximum value of Cant emax
Cant Deficiency (D)
Cant deficiency = x1-xA
Where,
xA = Actual cant provided as per average speed
x1 = Cant required for a higher speed train.
eth = eact+D
Where, eth = theoretical cant
eact = Actual cant
D = Cant deficiency.
Transition Curve (Cubic paraboa)
Equation of Transition curve:
(a) shift (s)
Where, S = shift in ‘m’
L = Length of transition carve in ‘m’
R = Radius of circular curve in ‘m’
(b) Length of Transition Curve: According to Indian Railway.
Where,
L = Length of transition curve in ‘m’
Vmax = Maximum permissible speed in km/hr.
Cd = Cant deficiency in ‘cm’
Another Approach
L = maximum of (i), (ii), (iii) and (iv).
Where, (i) As per railway code, L = 4.4√R where L&R ‘m’
(ii) At the change of change of super elevation of 1 in 360.
(iii) Rate of change of cant deficiency. Say 2.5 cm is not exceeded.
(iv) Based on rate of change of radial acceleration with radial acceleration of 0.3048 m/s2.
Where, V is in m/s.
Extra Leteral Clearance on curves
(a) over throw or extra clearance needed of centre =
(b) End throw or extra clearance needed at end
Where,
L = End to end length of bogie
C = Centre to centre distance of two bogie.
R = Radius of curve.
(c) Lean (L)
Where, h = Height of vehical
E = Super elevation
G = Gauge.
(d) Total Extra Lateral Clearance Needed Outside in Curve
(e) Total Extra Lateral Clearance inside the Curve
E1 = Overthrow + Lean + Sway
Where, = Radius of curve in ‘mm’.
L = End to end length of bugie = 21340 mm for B.G = 19510 mm for M.G
H = height of bogie = 4025 mm for B.G
3350 mm for M.G
C = Bogie centres distance = 1475 mm for B.G
3355 mm for M.G
E = Super elevation in mm
G = 1.676 m for B.G = 1.0 m for m.G
Extra Clearance on Platforms
(a) For platforms situated inside of curve
= E2-41 mm.
(b) For platforms situated outside the curve
= E1-25 mm.
Gauge Widening on Curves
Where,
B = Right wheel base in meters.
= 6m for B.G
= 4.88 m for M.G
R = Radius of curve in m.
L = Leap of flange in ‘m’.
h Depth of wheel flange below rails in cm.
D = Diameter of wheel in cm.
We = Gauge widening in cm.
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