Answer: The probability of a leap year having 53 Sundays is 2/7.
In a leap year, there are 366 days. To find the total number of weeks in that year divide 366 by 7 (as a week contains 7 days) and we get 2 as Remainder and 52 as Dividend. It indicates there will be 52 weeks and 2 extra days in a leap year.
The possibilities for two extra days will be: (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday) and (Sunday, Monday). The total outcome is 7 whereas the favourable outcome is 2. Hence, the probability of a leap year having 53 Sundays is 2/7.
Summary:
Find the Probability of a Leap Year having 53 Sundays
The probability of a leap year having 53 Sundays is 2/7. Probability can be calculated by using the formula Probability = Favourable Outcomes/Total Outcomes.
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