Combined Correction for a Distance of 2500 m is
By BYJU'S Exam Prep
Updated on: September 25th, 2023
Combined correction for a distance of 2500 m is-
- 0.49 m
- 0.07 m
- 0.42 m
- 0.56 m
Answer: C. 0.42 m
Table of content
Combined correction for a distance of 2500 m is 0.42 m.
Solution
Correction due to curvature,
CC=d2/2R
where,
d = horizontal distance between 2 points (in km)
R = radius of curvature of earth = 6370 kms
CC=0.0785d2
d is substituted in kms and CC value will be in m
Correction due to curvature is always negative
Correction due to refraction,
CR=17 CC
CR =0.0112d2
d = horizontal distance between 2 points (in km)
CR = corrections due to refraction (in m)
Correction due to refraction is always positive
Combined correction,
C = CR – CC
C= 1/7CC – CC
C= –6/7 CC
C= -0.0673d2
d is substituted in kms and C value will be in m
Combined correction for a distance of 2500 m is
C=0.0673×2.52 (negative)
(d = 2500 m = 2.5 km)
C = 0.42 m
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