# Calculate the volume occupied by 28u nitrogen gas

By BYJU'S Exam Prep

Updated on: September 13th, 2023

Let us consider the condition at STP, the molar mass of an element given in u has 1 molecule of an element.

It is given that 28u of nitrogen gas has 1 molecule of nitrogen gas

At STP, 1 molecule of nitrogen gas has 22.4 L

1 molecule of nitrogen gas has 6.022 x 1023 molecules of nitrogen gas which has 22.4 L of nitrogen gas

Number of moles of nitrogen gas of 28u having 1 molecule of nitrogen gas = 28/ (6.022 x 1023 x 28)

= 1/6.022 x 1023 [As 1 mole of nitrogen has 6.022 x 102 3 molecules]

Volume occupied by 28u nitrogen gas = 1/(6.022 x 1023 ) x 22.4 L

= 1/(6.022 x 1023 ) x 22400 mL

= 3.719 x 10⁻2 ⁰ mL of N2 gas

Therefore, the volume occupied by 28u nitrogen gas is 3.719 x 10⁻2 ⁰ mL of N2 gas.

Summary:

## Calculate the volume occupied by 28u nitrogen gas.

The volume occupied by 28u nitrogen gas is 3.719 x 10⁻2 ⁰ mL of N2 gas.

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