Calculate the volume occupied by 28u nitrogen gas
By BYJU'S Exam Prep
Updated on: September 13th, 2023
Let us consider the condition at STP, the molar mass of an element given in u has 1 molecule of an element.
It is given that 28u of nitrogen gas has 1 molecule of nitrogen gas
At STP, 1 molecule of nitrogen gas has 22.4 L
1 molecule of nitrogen gas has 6.022 x 1023 molecules of nitrogen gas which has 22.4 L of nitrogen gas
Table of content
Number of moles of nitrogen gas of 28u having 1 molecule of nitrogen gas = 28/ (6.022 x 1023 x 28)
= 1/6.022 x 1023 [As 1 mole of nitrogen has 6.022 x 102 3 molecules]
Volume occupied by 28u nitrogen gas = 1/(6.022 x 1023 ) x 22.4 L
= 1/(6.022 x 1023 ) x 22400 mL
= 3.719 x 10⁻2 ⁰ mL of N2 gas
Therefore, the volume occupied by 28u nitrogen gas is 3.719 x 10⁻2 ⁰ mL of N2 gas.
Summary:
Calculate the volume occupied by 28u nitrogen gas.
The volume occupied by 28u nitrogen gas is 3.719 x 10⁻2 ⁰ mL of N2 gas.
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