A charge q is placed at the center of the line joining two equal charges Q. The system of three charges will be in equilibrium if q is equal to

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Updated on: September 13th, 2023

(a) -Q/2

(b) -Q/4

(c) Q/2

(d) Q/4

The solution to the equation is option (b) -Q/4

A state of equilibrium refers to a condition where the system of three charges remains stationary without any net force acting on any of the charges. In other words, the electrostatic forces between the charges balance each other out, resulting in a stable configuration.

Equilibrium will be achieved when Q is Equal to

From the question, A charge q is placed at the center of the line joining two equal charges Q. To determine the value of q that will result in an equilibrium of the system, we need to consider the electrostatic forces acting on each charge. The system of three charges will be in equilibrium if q is equal to:

q is placed between the two charges q

The given situation can be depicted as:

For the system to be in equilibrium

FBA + FBC = 0

FBA = – FBC

It can be written as

KQ2/ (2x)2 = -KQq/ x2

So we get

q = -Q/4

The system to be in equilibrium condition is q = -Q/4

Therefore, the system of three charges will be in equilibrium if q is equal to -Q/4.

Summary:

A charge q is placed at the center of the line joining two equal charges Q. The system of three charges will be in equilibrium if q is equal to?

A charge q is placed at the center of the line joining two equal charges Q. The system of three charges will be in equilibrium if q is equal to -Q/4. As a result of the state of equilibrium, the electrostatic forces between the charges will end up balancing each other out and result in a stable configuration.

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