A carnot engine, having an efficiency of η = 1/10 is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is (a). 99 J (b). 90 J (c). 1 J (d). 100 J
By BYJU'S Exam Prep
Updated on: September 13th, 2023
Given, that a Carnot engine has an efficiency of η = 1/10
Work done on the system, W = 10 J
We have to find the amount of energy absorbed from the reservoir at lower temperatures.
The Carnot engine is a theoretical thermodynamic cycle proposed by Leonard Carnot.
It estimates the maximum possible efficiency that a heat engine can possess during the conversion process of heat into work.
In simple words, the Carnot engine describes the conversion of heat to work.
The coefficient of performance of a refrigerator,
ꞵ = 1-η / η
So, ꞵ = 1 – (1/10) / (1/10)
= (9/10) / (1/10)
ꞵ = 9
We know, ꞵ = QL/W
QL = ꞵxW
= 9 x 10
= 90 J
Therefore, the amount of energy absorbed is 90 J.
Summary:
A Carnot engine, having an efficiency of η = 1/10 is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at a lower temperature is (a). 99 J (b). 90 J (c). 1 J (d). 100 J
A Carnot engine, having an efficiency of η = 1/10 is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at a lower temperature is 90 J.
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