The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
By BYJU'S Exam Prep
Updated on: September 25th, 2023
The age of the youngest child is 4 years. The method used to solve this question is algebraic substitution and solving a linear equation. By assigning a variable to the unknown quantity (age of the youngest child in this case) and setting up an equation based on the given information, we can solve for the variable and find the solution.
Table of content
Algebraic Equations
Algebraic equations are mathematical expressions that use variables, constants, and mathematical operations to represent relationships between quantities. These equations are written in the form of equality, with an expression on one side of the equation equal to another expression on the other side. The goal of algebraic equations is to find the values of the variables that satisfy the equation.
For example- 2x + 3 = 9
In this equation, “x” is the variable, and we want to find the value of “x” that makes the equation true. By solving the equation, we can determine that “x” is equal to 3.
Solution:
Let’s assume the age of the youngest child as x.
According to the given information, the ages of the five children are x, x + 3, x + 6, x + 9, and x + 12 (since they are born at intervals of 3 years each).
The sum of their ages is given as 50:
x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
Simplifying the equation:
5x + 30 = 50
Subtracting 30 from both sides:
5x = 20
Dividing both sides by 5:
x = 4
Therefore, the age of the youngest child is 4 years.
Summary:
The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. The age of the youngest child is 4 years. To solve this type of question, we can use a combination of algebraic equations and basic arithmetic.
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