# A train starting from a railway station and moving with uniform acceleration attains a speed of 40km/h in 10 minutes. Find its acceleration in the units of m/s².

By BYJU'S Exam Prep

Updated on: September 25th, 2023

A train starting from a railway station and moving with uniform acceleration attains a speed of 40km/h in 10 minutes. The acceleration in the units of m/s² is 0.0185. The rate at which an object’s velocity changes over time is known as acceleration. It has both a direction and a magnitude because it is a vector quantity. Calculations show that acceleration (a) is equal to the product of the velocity (v) and time (t) changes.

## Acceleration of Train

Acceleration can be calculated using the following formula:

Acceleration (a) = Change in velocity (Δv) / Change in time (Δt)

where, t denotes the change in time and v denotes the change in velocity. In the metric system, acceleration is commonly expressed in units of metres per second squared (m/s2).

It’s important to note that acceleration is not only related to changes in speed but also to changes in direction. For example, when an object moves in a circular path at a constant speed, it experiences acceleration because its direction is continuously changing.

Solution

Initial speed u = 0 m/s2

Final velocity v = 40 km/h = 40 x 5/18 = 100/9 m/s

Time t = 10 mins = 600 sec

Let us use the first equation of motion

v = u + at

Substituting the values we get

100/9 m/s = 0 + 600s x a

So we get

a = 100/(9 x 600) m/s2

a = 0.0185 m/s2

Therefore, its acceleration is 0.0185 m/s2.

Summary

## A train starting from a railway station and moving with uniform acceleration attains a speed of 40km/h in 10 minutes. Find its acceleration in the units of m/s2.

A train starting from a railway station and moving with uniform acceleration attains a speed of 40km/h in 10 minutes. Its acceleration in the units of m/s2 is 0.0185.

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