A point object is placed at a distance of 60 cm from a convex lens of a focal length of 30 cm. If a plane mirror were put perpendicular to the principal axis of the lens and at a distance of 40cm from it, the final image would be formed at a distance of –

l1 is the first image by the lens

An image will be produced by the plane image at a 20 cm distance to the left of it

For the second refraction from a convex lens

u = -20 cm

v = ?

f = 30 cm

Using the lens formula

1/v – 1/(-20) = 1/30

v = -60 cm

The final image is virtual and at a distance of 60 – 40 = 20 cm from the plane mirror.

Therefore, the final image would be formed at a distance of 20 cm from the plane mirror; it would be a virtual image.

Summary:

A point object is placed at a distance of 60 cm from a convex lens of a focal length of 30 cm. If a plane mirror were put perpendicular to the principal axis of the lens and at a distance of 40cm from it, the final image would be formed at a distance of –

A point object is placed at a distance of 60 cm from a convex lens of a focal length of 30 cm. If a plane mirror were put perpendicular to the principal axis of the lens and at a distance of 40cm from it, the final image would be formed at a distance of 20 cm from the plane mirror; it would be a virtual image.

Related Questions:-

• Explain The Process Of The Breakdown Of Glucose By Various Pathways?
• The Density Of A 3m Solution Of Nacl Is 1 Point 25 Gram Per Ml Calculate The Molality Of The Solution?
• All Formulas From Lesson Some Basic Concepts Of Chemistry?