A charge q is placed at the center of the line joining two equal charges Q. The system of three charges will be in equilibrium if q is equal to

Equilibrium will be achieved when Q is Equal to

From the question, A charge q is placed at the center of the line joining two equal charges Q. To determine the value of q that will result in an equilibrium of the system, we need to consider the electrostatic forces acting on each charge. The system of three charges will be in equilibrium if q is equal to:

q is placed between the two charges q

The given situation can be depicted as:

For the system to be in equilibrium

FBA + FBC = 0

FBA = - FBC

It can be written as

KQ²/ (2x)² = -KQq/ x²

So we get

q = -Q/4

The system to be in equilibrium condition is q = -Q/4

Therefore, the system of three charges will be in equilibrium if q is equal to -Q/4.

Summary:

A charge q is placed at the center of the line joining two equal charges Q. The system of three charges will be in equilibrium if q is equal to?

A charge q is placed at the center of the line joining two equal charges Q. The system of three charges will be in equilibrium if q is equal to -Q/4. As a result of the state of equilibrium, the electrostatic forces between the charges will end up balancing each other out and result in a stable configuration.

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