A charge q is placed at the center of the line joining two equal charges Q. The system of three charges will be in equilibrium if q is equal to (a). -Q/2 (b). -Q/4 (c). Q/2 (d). Q/4

By Shivank Goel|Updated : August 17th, 2022

From the question, A charge q is placed at the center of the line joining two equal charges Q. The system of three charges will be in equilibrium if q is equal to

q is placed between the two charges q

The given situation can be depicted as

A charge q is placed at the center of the line joining two equal charges Q

For the system to be in equilibrium

FBA + FBC = 0

FBA = - FBC

It can be written as

KQ2/ (2x)2 = -KQq/ x2

So we get

q = -Q/4

The system to be in equilibrium condition is q = -Q/4

Therefore, the system of three charges will be in equilibrium if q is equal to -Q/4.

Summary:

A charge q is placed at the center of the line joining two equal charges Q. The system of three charges will be in equilibrium if q is equal to (a). -Q/2 (b). -Q/4 (c). Q/2 (d). Q/4

A charge q is placed at the center of the line joining two equal charges Q. The system of three charges will be in equilibrium if q is equal to -Q/4.

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