# A carnot engine, having an efficiency of η = 1/10 is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is (a). 99 J (b). 90 J (c). 1 J (d). 100 J

By Shivank Goel|Updated : August 16th, 2022

Given, that a Carnot engine has an efficiency of η = 1/10

Work done on the system, W = 10 J

We have to find the amount of energy absorbed from the reservoir at lower temperatures.

The Carnot engine is a theoretical thermodynamic cycle proposed by Leonard Carnot.

It estimates the maximum possible efficiency that a heat engine can possess during the conversion process of heat into work.

In simple words, the Carnot engine describes the conversion of heat to work.

The coefficient of performance of a refrigerator,

ꞵ = 1-η / η

So, ꞵ = 1 - (1/10) / (1/10)

= (9/10) / (1/10)

ꞵ = 9

We know, ꞵ = QL/W

QL = ꞵxW

= 9 x 10

= 90 J

Therefore, the amount of energy absorbed is 90 J.

Summary:

## A Carnot engine, having an efficiency of η = 1/10 is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at a lower temperature is (a). 99 J (b). 90 J (c). 1 J (d). 100 J

A Carnot engine, having an efficiency of η = 1/10 is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at a lower temperature is 90 J.

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