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Number of lone pairs of electrons present in XeF2 molecule is?
By BYJU'S Exam Prep
Updated on: September 25th, 2023
(A) 5
(B) 4
(C) 6
(D) 3
Number of lone pairs of electrons present in XeF2 molecule is 3. Xe is a Noble gas element that may be found in group 8 of the periodic chart. Consequently, Xe has 8 valence electrons. F is in group 7 of the periodic table, which is the halogen group. Consequently, F has 7 valence electrons.
Table of content
Loan Pairs of Electrons Present in XeF2
Total no. of valence electrons of XeF2 = (No. of Xe atoms x No. of valence electrons of Xe) + (No. of F atoms x No. of valence electrons of F) = (1×8)+(2×7)
= 22 electrons
- Currently, there are two Xe–F bonds and five electron pairs in XeF2.
- Two of these five are bond pairs, therefore there are five lone pairs of electrons on each of these XeF2 is 3.
Uses of Xenon Difluoride – XeF2
- The hetero element in an organometallic compound is used to be oxidised and fluorinated, but it is not harmful to the alkyl or aryl groups.
- The oxidation of iodine to periodate is used as a very practical method for the detection and measurement of very minute levels of iodine and iodide.
- used as an antiseptic, a laser power source, and to power tracers. As fuel for ion engines, it is chosen for use in deep space to power spacecraft.
Summary:
Number of lone pairs of electrons present in XeF2 molecule is? (A) 5 (B) 4 (C) 6 (D) 3
The XeF2 molecule has three lone pairs of electrons. Group 8 of the periodic table contains the Noble gas element Xe. Xe thus has 8 valence electrons.
