Identify the oxidized and reduced compound in the given reaction CuO (s) + H2(g) → Cu(s) + H2O(l) Copper oxide + Hydrogen gas → Copper + Water

Oxidized and Reduced Substances

CuO (s) → Cu (s)

Copper oxide → Copper

+2 → 0

Hydrogen gas is oxidized here as an oxygen atom is added to it. Also, the oxidation number of hydrogen changes from 0 to +1.

Uses of Copper Oxide

1. Used in antifouling coatings for boat and ship floors. It is effective corrosion control.
2. Used for coating glass and porcelain.
3. Used as a p-type semiconductor material used in the manufacture of photocells and rectifiers for light meters.
4. Used as fungicide and seed dressing.

Therefore, in the given reaction oxidized substance is hydrogen and the reduced substance is copper oxide.

Summary:

Identify the oxidized and reduced compound in the given reaction: CuO (s) + H2(g) → Cu(s) + H2O(l)

In the above reaction, copper oxide is the reduced substance and hydrogen is the oxidized substance. Copper(I) Oxide is known as cuprous oxide which is an inorganic compound with Cu2O as a chemical formula.