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Identify the oxidized and reduced compound in the given reaction CuO (s) + H2(g) → Cu(s) + H2O(l) Copper oxide + Hydrogen gas → Copper + Water
By BYJU'S Exam Prep
Updated on: September 25th, 2023
Oxidized compounds are those whose oxidation number increases, or they gain oxygen in a process, or they lose electrons or electronegative species combine with them in a reaction. Reduced substances are those whose oxidation number lowers, meaning they lose oxygen or gain electrons, or electropositive species join with them in a reaction. The oxidation number of copper changes from +2 to 0. Also, the oxygen atom is removed from copper oxide. Therefore copper oxide is reduced here.
Table of content
Oxidized and Reduced Substances
CuO (s) → Cu (s)
Copper oxide → Copper
+2 → 0
Hydrogen gas is oxidized here as an oxygen atom is added to it. Also, the oxidation number of hydrogen changes from 0 to +1.
Uses of Copper Oxide
- Used in antifouling coatings for boat and ship floors. It is effective corrosion control.
- Used for coating glass and porcelain.
- Used as a p-type semiconductor material used in the manufacture of photocells and rectifiers for light meters.
- Used as fungicide and seed dressing.
Therefore, in the given reaction oxidized substance is hydrogen and the reduced substance is copper oxide.
Summary:
Identify the oxidized and reduced compound in the given reaction: CuO (s) + H2(g) → Cu(s) + H2O(l)
In the above reaction, copper oxide is the reduced substance and hydrogen is the oxidized substance. Copper(I) Oxide is known as cuprous oxide which is an inorganic compound with Cu2O as a chemical formula.
