Age-Related Questions are the most asked questions in the banking exams and students find it a little tough and confusing. However, this topic is an important section of Quantitative Aptitude, and today, you will learn the basic tricks which will dislodge your fear of solving Age-related questions in any banking exam. Lean on this article to learn the basic tricks to solve it without any hustle. The below given easy methods are going to help the aspirants in all your exam. So, save your time and speed up the competitive exam.
To make the chapter easy for you all, we are providing you with some Basic Concepts and Tricks on Age-Related Questions which will surely make the chapter easy for you all.
Have a look at the following Age Related questions:-
Question. 1: The present ages of R and S are in the ratio 7:6. Nine years from now, the age of R would be double of S’s age 3 years ago. What is the present age of S?
Let the present ages of R and S be R and S years, respectively.
R/S= 7/6 ⇒ 6R = 7S…..(1)
(R + 9)/(S - 3) = 2 ⇒ R + 9 = 2S – 6 ⇒ 2S – R = 15…..(2)
Solving equations (1) and (2)
R = 21 S = 18
Question. 2: The ratio of the present ages of A to B is 2:3. Four years hence, the ratio of their ages will be 5:7. What is the present age of A?
Solution: Let the present ages of A and B be 2x and 3x respectively. Therefore,
After 4 years,
A’s age = (2x + 4) years
B’s age = (3x + 4) years
2x + 4 / 3x + 4 = 5/7
7(2x + 4) = 5(3x + 4)
14x + 28 = 15x + 20
x = 8
Thus, A’s present age = 8 × 2 = 16 years
Question. 3: Ram’s mother was 4 times as old as Ram 12 years ago. After 12 years, she will twice as old as Ram. What is the present age of Ram’s mother?
Let, present age of Ram = x and present age of his mother = y
Ram’s mother was 4 times as old as Ram 12 years ago.
According to problem,
⇒y – 12 = 4(x – 12)
⇒y = 4x – 36 ……… (1)
After 12 years, she will twice as old as Ram.
According to problem,
⇒y + 12 = 2(x + 12)
⇒y = 2x + 12 ……… (2)
From (1) and (2) we get,
⇒4x – 36 = 2x + 12
⇒2x = 48
⇒x = 24
Putting the value x= 24 in (2) we get,
⇒y = 2 × 24 + 12
⇒y = 60
∴present age of Ram’s mother = 60 years
Question. 4: Vivek said to Ram “I am 3 times as old as you were when I was half of what your age will be 3 years from now”. If sum of their ages is 50 years, find the age of Ram. (in years).
Let the present ages of Vivek and Ram be ‘a’ and ‘b’ respectively.
Given, Vivek said to Ram “I am 3 times as old as you were when I was half of what your age will be 3 years from now”.
⇒Vivek’s age = 3 × (Ram’s age when Vivek’s age was half of what Ram’s age will be 3 years from now)
a = 3 X (b - (a - (b + 3)/2)
⇒a = 3b – 3a + 3b/2 + 9/2
⇒4a = 9b/2 + 9/2
⇒8a = 9b + 9
⇒a = (9b + 9)/8
Given, sum of their ages is 50 years.
⇒a + b = 50
⇒(9b + 9)/8 + b = 50
⇒17b + 9 = 400
⇒b = 23 years
Question. 5: The sum of the ages of Vidit, Rahul, and Pravin is 93 years. 10 years ago, the ratio of their ages was 2:3:4. What is the present age (in years) of Pravin?
Solution: Let their ages 10 years ago be 2z, 3z, and 4z respectively.
Then their present ages will be
Vidit's age = 2z + 10
Rahul's age = 3z + 10
Pravin's age = 4z + 10
Vidit's age + Rahul's age + Pravin's age = (2z + 10) + (3z + 10) + (4z + 10)
Vidit's age + Rahul's age + Pravin's age = 9z + 30
The sum of their present ages is 93.
9z + 30 = 93
9z = 63
z = 7
Therefore, present age of Pravin = 4z + 10 = 4 X 7 + 10 = 38 years
Note: Just try to make two equations and then solve them to get your answer.
Question 6: 8 years ago, the ratio of the ages of Priyanka and Ritika was 11:17 respectively and 2 years hence, the ratio of their ages will be 8:11. If the ratio of the present ages of Ritika to Manisha is 7:8, what will be the age of Manisha after 3 years?
Let 8 years ago,
The age of Priyanka = 11x years
The age of Ritika = 17x years
According to the question,
11x+10/17x+10 = 8/11
⇒ 121x + 110 = 136x + 80
⇒ 15x = 30
⇒ x = 2
Present age of Priyanka = 11 × 2 + 8 = 30 years
Present age of Ritika = 17 × 2 + 8 = 42 years
Present age of Manisha = 42/7 × 8 = 48 years
Required age of Manisha = 48 + 3 = 51 years
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