Find the Area of the Four Walls of a Cuboidal room having length, breadth, and height in the ratio 2 : 5 : 4 and their Sum is 55 cm

By K Balaji|Updated : October 6th, 2022
  1. 1500 cm2
  2. 1520 cm2
  3. 1400 cm2
  4. 1380 cm2

The area of the four walls of a cuboidal room with dimensions of 2: 5: 4 (length, width, and height), and a sum of 55 cm, is 1400 cm2.

It follows that

Ratio Length : Breadth : Height = 2 : 5 : 4

Sum Length + Breadth + Height = 55 cm

By using the formula we get

Area can be found using the formula 2 H (L + B)

Let us calculate

Consider length, breadth, and height as 2x, 5x, and 4x.

It can be written as

2x + 5x + 4x = 55 cm

By adding them we get

11x = 55 cm

Now on dividing both sides by 11

x = 5 cm

We get

Length L = 10 cm

Breadth B = 25 cm

Height H = 20 cm

By calculating the area = 2 × 20 (10 + 25) = 1400 cm2

Therefore, the area of four walls is 1400cm2

Summary:-

Find the Area of the four walls of a Cuboidal room having length, breadth, and height in the ratio 2 : 5 : 4 and their Sum is 55 cm - 1. 1500 cm^2 2. 1520 cm^2 3. 1400 cm^2 4. 1380 cm^2

1400cm2 is the area of the four walls of a cuboidal room having their sum is 55 cm and breadth, length, and height in the ratio 2 : 5 : 4

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