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The increasing order of the bond order of O2, O2-. O2+ and O22-?
By BYJU'S Exam Prep
Updated on: September 25th, 2023
The increasing order of the bond order of O2, O2-. O2+ and O22- is O22- < O2- < O2 < O2+. The total number of covalently bound electron pairs between two atoms in a molecule determines the bond order of a covalent bond. It can be determined by sketching the molecule’s Lewis structure and adding up all the electron pairs that exist between the relevant atoms.
- The bond order for single bonds is 1.
- The bond order for double bonds is two.
- The bond order for triple bonds is 3.
Table of content
Bond Order
- Every molecule has a hierarchy of bonds.
- Each molecule has a unique bond configuration.
- Half of the difference between the number of electrons in bond-free (nonbonding) and bond-filled (bonded) molecular orbitals is used to compute the bond order.
The formula to calculate the bond order:
BO = NB – NA/2
The quantity of electrons present in the bonding and antibonding molecular orbitals, is NA, NB
Step 1: Bond order calculation for a particular species:
BO for O2 = ½ (10 – 6) = 2
BO for O2- = ½ (10 – 7) = 1.5
BO for O2+ = ½ (10 – 5) = 2.5
BO for O22- = ½ (10 – 8) = 1
Step 2: Let us arrange according to increasing bond length
O22- < O2- < O2 < O2+
Summary:
The increasing order of the bond order of O2, O2-. O2+ and O22-?
O22- < O2- < O2 < O2+ is the increasing order of the bond order of O2, O2-. O2+ and O22- . The bond order is found by the total covalently bound electron pair numbers present in two atoms of a molecule.
