Solve: Iron (Fe) + oxygen (O2) + water (H2O) = ?

By BYJU'S Exam Prep

Updated on: September 25th, 2023

4 Fe (s) + 3O2 (g) + x . H2O (l) → 2Fe2O3, Iron Oxygen WaterFerric oxide (Rust) – Ferric oxide, also referred to as rust, develops when iron interacts with oxygen and water. The chemical reaction that is balanced can be seen as – 4 Fe (s) + 3O2 (g) + x. H2O (l) → 2Fe2O3

Iron Oxygen Water Ferric oxide (Rust)

In a water-rich environment, such as highly humid air, oxygen and iron undergo a redox reaction that results in the formation of rust. Rusting of iron is characterised by the formation of a layer of a red, flaky substance that readily breaks into powder. The rusting process can be stopped or slowed down with a coat of oil. High-quality paint will also help by keeping moisture from getting to the metal, which will slow down the rusting process. Therefore, 4 Fe (s) + 3O2 (g) + x. H2O (l) → 2Fe2O3

Iron Oxygen WaterFerric oxide (Rust) is the end result of the entire interaction between iron, oxygen, and water.


Solve: Iron (Fe) + oxygen (O2) + water (H2O) = ?

Rust is the result of the reaction between iron, oxygen, and water. Ferric oxide is also known as rust. The balanced chemical reaction can be visualised as 4 Fe (s) + 3O2 (g) + x. H2O (l) → 2Fe2O3.

Our Apps Playstore
SSC and Bank
Other Exams
GradeStack Learning Pvt. Ltd.Windsor IT Park, Tower - A, 2nd Floor, Sector 125, Noida, Uttar Pradesh 201303
Home Practice Test Series Premium