# Calculate the volume occupied by one molecule of water. (Given density 1 g cm-3)

By BYJU'S Exam Prep

Updated on: September 25th, 2023

The volume occupied by one molecule of water is 2.98 x 10-23 cm3. Steps to Calculate the volume occupied by one molecule of water:

Step: 1 How to determine how much space a mole of water takes up:

Given that the Density of water: dw = 1g cm-3

We know that Density = mass/ volume

• Volume of water = 18 x 1 cm3/ mol
• Volume of water = 18 cm3/ mol

Step: 2 calculating the space filled by a single water molecule:

Volume of one molecule of water = 18/6.022 x 1023 = 2.98 x 10-23 cm3

Hence, the volume occupied by one molecule of water is 2.98 x 10-23 cm3.

### Molecule of Water

One of the natural resources that can be discovered in sufficient quantities is water. It is a vital source for the continuation of life on Earth. It is extensively used for many different things, including drinking, bathing, cleaning, cooking, irrigation, and other domestic and commercial uses.

There are numerous water sources. On the surface of the Earth, water covers around 97% of the area. These are the top three water sources:

• Rainwater.
• Waterbodies like wells and springs are considered to be groundwater.
• Surface water is any water that is on the surface of another body of water, such as the sea, oceans, reservoirs, rivers, streams, ponds, lakes, and tanks.

Summary:

## Calculate the volume occupied by one molecule of water. (Given density 1 g cm-3)

The volume occupied by one molecule of water is 2.98 x 10-23 cm3. The primary component of streams, oceans, and lakes on the surface of the world is water, a colorless, transparent molecule.

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