# An electric dipole is placed at an angle of 30° with an electric field intensity of 2 × 105 N/C. It experiences a torque equal of 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is?

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Updated on: September 25th, 2023

(a) 5 mC

(b) 7μC

(c) 8 mC

(d) 2 mC

The charge on the dipole, if the dipole length is 2 cm, is 2 mC. Steps to Know the charge on the dipole, if the dipole length is 2 cm:

Step 1: It is given:

Angle θ = 30°

Torque (τ) = 4Nm

Electric field (E) = 2 × 105 N/C

Dipole length (l) = 2 cm = 2 x 10-2 m

Step 2: Now we have to Calculate the charge on the dipole:

An electric dipole in a consistent electric field feels a torque () determined by

τ = pEsinθ

Where,

p = dipole moment

= q x l

Torque is:

τ = qlE sinθ

q = τ/lE sinθ

Substituting the values,

q = 4Nm/ (2 x 10-2 m x 2 × 105 N/C x sin 30°)

On simplifying we get

q = 4/ (4 x 103 x ½)

q = 2 x 10-3 C

q = 2 mC

A pair of opposing charges, q and -q, separated by a distance, d, is referred to as an electric dipole. Electric dipoles in space always point in the direction of positive charge q from negative charge -q. The dipole’s center is defined as the intersection of q and -q. A pair of electric charges with two opposite signs and equal magnitudes spaced apart is the simplest type of electric dipole.

Summary:

## An electric dipole is placed at an angle of 30° with an electric field intensity of 2 × 105 N/C. It experiences a torque equal of 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is?

An electric dipole is placed at an angle of 30° with an electric field intensity of 2 × 105 N/C. It experiences a torque equal of 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is 2 mC.

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