# A racing car has a uniform acceleration of 4 ms-2. What distance will it cover in 10s after start?

By BYJU'S Exam Prep

Updated on: September 25th, 2023

A racing car has a uniform acceleration of 4 ms-2. The car will cover a distance of 200 m in 10s after starting. While distance and displacement appear to signify the same thing, they actually have very different definitions and meanings. A scalar quantity known as distance measures “how much ground an object has traversed” while moving. An object’s total change in position is referred to as displacement, a vector variable that measures “how far out of place an object is.” The rate at which velocity changes in relation to time is known as acceleration.

### Steps to Calculate the Distance Covered

Step 1: Given that

Time period, t = 10 s

Final acceleration, a = 4 ms-2

The automobile accelerates consistently. This indicates that it was initially at rest.

Initial velocity, u = 0 ms-1

Step 2: Formula used

We know that the second equation of motion is,

s = ut + ½ at2, where s is the distance covered

Step 3: Now we have to calculate the distance covered

By substituting the values in the above equation, we get

s = 0 x 10 + ½ x 4 x 102

s = 200 m

As a result, after starting, the car will travel 200 meters in 10 seconds.

Summary:

## A racing car has a uniform acceleration of 4 ms-2. What distance will it cover in 10s after start?

The constant acceleration of a racing car is 4 ms-2. After starting, the vehicle will travel 200 meters in 10 seconds. As both distance and displacement explain the same thing, the actual meaning and definitions are different.

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