Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction given below – CaCO3(s)+2HCl(aq)⟶CaCl2(aq)+CO2(g)+H2O(l). what mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl?

By BYJU'S Exam Prep

Updated on: September 25th, 2023

0.6844
0.9375
0.4265
0.2785

The mass of CaCO3 required to react completely with 25 mL of 0.75 M HCl is 0.9375.

The given equation is CaCO3+2HCl –> CaCl2 + H2O + CO2

Consequently, the mole ratio of calcium carbonate to HCl is 1:2.

Number of moles of HCl = molarity x volume

= 0.75×0.025 Litres = 0.01875 moles

Therefore, the amount of calcium carbonate should be equal to half the amount of HCl.

Number of moles of CaCO3 = 1/2 x 0.01875 = 0.009375

Molar mass of CaCO3= 100u

Mass of calcium carbonate = moles x molar mass = 0.009375 x 100= 0.9375g

So option (2) is correct

Table of content

1. Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction given below – CaCO3(s)+2HCl(aq)⟶CaCl2(aq)+CO2(g)+H2O(l). what mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl?

Applications of Calcium Carbonate

Most of the calcium carbonate is used in the pulp and paper industries. It allows for the development of a whiter, higher-quality pigment than other minerals and can be used as a filter and pigment.
Calcium carbonate is used in the construction industry as a filler in concrete to improve its strength and appearance and to cleanse metals for use in building applications.
To deliver calcium to plants and maintain the soil’s pH, calcium carbonate is also used in fertilisers.
In addition, calcium carbonate can be used as a vitamin supplement and as an ingredient in food products for both people and animals.
Calcium carbonate is used in water and wastewater treatment facilities to remove pollutants and acidity.

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