Balance the equation: Hydrogen Sulfide gas burns in the air to give Water and Sulfur dioxide.

Steps to balance the Equation

Step 1:

Create the chemical equation with the unbalance. Let’s consider the indicated response. That is how sulphur dioxide and water are produced when hydrogen sulphide gas burns in the atmosphere. H2S + O2 → SO2 + H2O

Step 2:

Calculate the number of atoms. List the atoms of each element on the reactant and product sides, respectively.

Atom	Reactant Side	Product Side
H	1	2
S	1	1
O	2	3

Step 3:

In a chemical equation, add coefficients to balance the mass. The coefficients that must be added must be whole numbers, and each coefficient must be applied to every atom in that specific molecule.

Example –

In 2H2O, 4 hydrogen atoms and 2 oxygen atoms are implied. Balance the lone oxygen atom first, then go on to the hydrogen atom. In this case, sulphur will be balanced before oxygen. Use the trial-and-error approach. Adding 2 hydrogen will result in 4 on both the reactants’ and the product’s sides. Therefore, 2 H works and 2 hydrogen sulphide result in 2H2O. To balance oxygen, the same trial-and-error process is being used. When it comes to 3O2, there are 6 oxygen atoms on both the reactant and product sides. As a result, the correct chemical equation is: 2H2S + 3O2 → 2SO2 + 2H2O

For verification, rewrite the table as follows:

When we enter the values into the table, we obtain

Atom	Reactant Side	Product Side
H	4	4
S	2	2
O	6	6

The atoms are now evenly distributed on both the reactant and product sides. Consequently, the chemical equation describing how hydrogen sulphide gas burns in the presence of oxygen to produce water and sulphur dioxide is 2H2S + 3O2 → 2SO2 + 2H2O

Summary:

Balance the equation: Hydrogen Sulfide gas burns in the air to give Water and Sulfur dioxide.

The balance of the equation is as follows: Hydrogen sulphide gas burns in the air to produce water and sulphur dioxide H2S (g) + O2 (g) → H2O (l) + SO2 (g) is 2H2S + 3O2 → 2SO2 + 2H2O.