How to Solve Approximation Questions? Tips & Tricks

By Amrit Gouda|Updated : April 29th, 2021

How to solve Approximation Question? Quantitative Aptitude section of the Banking exam consists of questions such as Simplification, Approximation, Number Series, Permutation & Combination, Quadratic Equation, Data Interpretation, Data Analysis, and other Miscellaneous questions.

How to solve Approximation Question? Quantitative Aptitude section of the Banking exam consists of questions such as Simplification, Approximation, Number Series, Permutation & Combination, Quadratic Equation, Data Interpretation, Data Analysis, and other Miscellaneous questions.

In most of the Banking Prelims exam, the major chunk of questions is asked from the topic Approximation and Simplification. They are very easy and requires good calculation skills. 

Here is a short study guide to help you crack questions on "Approximation“. To solve approximation questions, you must understand the basic rules of Simplification. 

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Basic Rules of Simplification

BODMAS Rule

It defines the correct sequence in which operations are to be performed in a given mathematical expression to find the correct value. This means that to simplify an expression, the following order must be followed -

B = Bracket,
O = Order (Powers, Square Roots, etc.)
D = Division

M = Multiplication
= Addition

S = Subtraction

1. Hence, to solve approximation questions correctly, you must apply the operations of brackets first. Further, in solving for brackets, the order - (), {} and [] - should be strictly followed. 
2.
Next you should evaluate exponents (for instance powers, roots etc.)

3. Next, you should perform division and multiplication, working from left to right. (division and multiplication rank equally and are done left to right).

4. Finally, you should perform addition and subtraction, working from left to right. (addition and subtraction rank equally and are done left to right).

EXAMPLE 1: Solve 12 + 22 ÷ 11 × (18 ÷ 3)^2 - 10

= 12 + 22 ÷ 11 × 6^2 - 10 (Brackets first)
= 12 + 22 ÷ 11 × 36 - 10 (Exponents)
= 12 + 2 × 36 - 10 = 12 + 72 - 10 (Division and multiplication, left to right)
= 84 - 10 = 74 (Addition and Subtraction, left to right)

EXAMPLE 2: Solve 4 + 10 - 3 × 6 / 3 + 4

= 4 + 10 - 18/3 + 4 = 4 + 10 - 6 + 4 (Division and multiplication, left to right)
= 14 - 6 + 4 = 8 + 4 = 12 (Addition and Subtraction, left to right)

Tips to Crack Approximation

Conversion of decimal numbers to the nearest number

To solve such questions, first, convert the decimal to the nearest value. Then simplify the given equation using the new values that you have obtained.

EXAMPLE 1: Solve 4433.764 - 2211.993 - 1133.667 + 3377.442

Here,
4433.764 = 4434
2211.993 = 2212
1133.667 = 1134
3377.442 = 3377

Now simplify, 4434 -  2212 - 1134 + 3377 = 4466

EXAMPLE 2: Solve 530 x 20.3% + 225 x 16.8%

Here, 20.3% becomes 20% and 16.8% becomes 17%
Now, simplify 530 x 20% + 225 x 17%
= 106 + 38.25 = 144.25

EXAMPLE 3: 38.97×15.02-27.94×10.02=(36+?)×4.92   As per the BODMAS rule, the priority in which the operations should be done is:

Note: Addition and subtraction can be treated on same priority (from left to right) when they are in consecutive order.

38.97×15.02-27.94×10.02=(36+?)×4.92
Approximating the value to the nearest integer:
39×15-28×10=(36+?)×5 
585-280=(36+?)×5 
305=(36+?)×5 
=36+? 
61=36+? 
?=61-36 
?=25

EXAMPLE 4 : √483.9915 + (7.0215)= ? *6.0212  - 1.02153   As per the BODMAS rule, the priority in which the operations should be done is:



Note:
 Addition and subtraction can be treated on the same priority (from left to right) when they are in consecutive order.

√483.9915 + (7.0215)= ? * 6.0212  - 1.02153
Approximating the value to the nearest integer:
√484+72 =?*6.0212-13
22+49=?×6-1
71+1=6?
72=6?
?=
?=12

EXAMPLE 5: 64% of (?) + (?)% of 76 = 76.89% of 286 + 73.87% of 147

This is written as:
⇒   (Cancel 100s)
⇒ 64 (?) + (?)76 = 77 × 286 + 74 × 147 
⇒ 140(?) = 22022 + 10878 
⇒ 140(?) = 32900 
⇒ (?) =  
Hence, (?) = 235

EXAMPLE 6: (√80.997 - √25.001) × (√120.98 + √16.02) = ?

Approximating the values: 
(√81 - √25) × (√121 + √16) = ? 
(9 - 5) × (11 + 4) = ? 
4 × 15 = ? 
? = 60

EXAMPLE 7: (14.99% of 4799.995)  ? = (170% of 7.111)2   2 
 ?  
 ? 5  

EXAMPLE 8: (89)2 + ? % of 560.30 + (14.99)2= 95.45*286   (89)2 + ? % of 560.30 + (14.99)2= 95.45*286 
7921 + 560x/100 + 225= 27170 
560x/100= 27170- 7921-225 
560x/100= 19024 
x= 3397  

EXAMPLE 9: 100/3 % of 768.9 + 25% of 161.2 – 68.12=?   100/3 % of 768.9 + 25% of 161.2 – 68.12=? 
= 100/3 * 1/100 *768 + 40 – 68 
= 256+ 40 -68 
= 228  

EXAMPLE 10: 795.002÷14.998+768.025÷11.985-1273.025÷19.022=x   x=795÷15+768÷12-1273÷19 
x=53+64-67 
x=50
   

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Posted by:

Amrit GoudaAmrit GoudaMember since Mar 2021
Community Associate at Gradeup. Cleared many bank exams.
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Manikandan N

Manikandan NAug 14, 2020

Thank u mam
Jagannath

JagannathSep 5, 2020

Excellent 👌👍👍
Sushmita Mallik
Very nice and very easy to understand by these solutions
Lally

LallyJul 2, 2021

Thank you ma'am
Mankaram Dewasi
Please Hindi
S.Batsha Miyan
Please can u shortcut please
S.Batsha Miyan
Please whatapp number
S.Batsha Miyan
Please guide iam handicapped students please hlp full

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