MPSC Combined Prelims Exam 2020-Problems on Simple Interest
Simple and Compound Interest is an important segment of the Arithmetic section under Quantitative Aptitude. To help you all understand these topics better, we are sharing study notes with an example so that you can tackle questions based on Simple Interest easily.
In this article, we will discuss the concepts of Simple Interest and talk about how to solve and approach the questions based on this topic.
Example 2: If the principal is 100 Rs. Difference of Simple Interest for 4yrs and 6yrs is Rs 8. Calculate the rate of simple interest.
Solution: In simple interest questions, interest always remains same for a year if the principal, rate of interest is constant for the same.
Let Interest for 4 yrs is I then interest for 6 yrs is (I+8)
interest for 2 yrs is Rs. 8
interest for 1 yr = 4
rate of interest = (4/100) × 100 = 4%
Example3: If the amount is (10/9) times of Principal and rate of interest and time both are numerically equal. Then, what is the rate of interest per annum?
Solution: Let Principal is P. Given, numerically R = T
Interest = Amount – principal
I = (10/9)P – P
I = P/9 (Interest is in the multiples of Principal)
Now, I =[(P×R×T)/100]
P/9 = (P× R× T)/100
R2 = 100/9 (using, R=T)
R = (10/3)%
We can also say the time period is (10/3)years.
Short approach: Whenever Interest is in multiple of Principal and Rate of Interest and Time period is equal.
Annual Instalments for Simple Interest:
Let's discuss a real example to understand instalment concepts:
A person deposit Rs.140 to bank every year up to 5 yrs . The bank gives him 5% rate of interest simple annually. And at the end of 5 yrs he get total amount of Rs.770
So, 140 is the instalment, time is 5 years rate of interest is 5% and the amount or debt is Rs.770
This Instalment is also known as annual payment. Debt is total amount, so don’t confuse between these two terms.
Installment = where A = debt, r = rate of interest and t = time period
Example4: What annual payment will discharge a debt of Rs.848 in 4yrs at 4% per annum simple interest?
In case if you forget formula then how to approach this question.
Let installment is X. There are 4 installments and rate of interest is also 4%
Debt (A) = four installments + (r%) × installments × (0+1+2+… (t-1))
So, 848 = 4X + (4%)(X)(0+1+2+3)
848 = 4X+
848 = 4X+
848 = 424X/100
X = 200
Some Important examples based on Simple Interest
Example5: A sum amounts to Rs. 702 in 2 years and Rs. 783 in 3 years. Calculate the sum, rate of interest and the amount after 5 years?
Amount for 2 years(A2) = 702
Amount for 3 years (A3)= 783
Interest for 1 year (I) = 783-702 = 81
So Sum = A2 – 2I = 702 – 2×81
= 702-162 = 540
rate of interest = (81/540)×100
Amount after 5 years = Sum+5I
= 540+ 5×81
Example6: A sum of money doubles itself in 3 yrs at a simple interest. In how many yrs will it amount to 8 times itself?
Solution: Doubles in 3 yrs
3 times in 3× 2 = 6yrs
4 times in 3× 3 = 9yrs
8 times in 3× 7 = 21yrs
Example7: Atul and Vijay are friends. Atul borrowed a sum of Rs.400 at 5% per annum simple interest from Vijay. He returns the amount with interest after 2 yrs. Vijay returns to Atul 2% of the total amount returned. How much did Atul receive?
Solution: After 2 yrs, amount returned to Vijay = 400+ (400*5*2)/100 = Rs 440
Amount returned to Atul = 2% of 440 = 8.8
Example8: Rs.4000 is divided into two parts such that if one part be invested at 3% and the other at 5%, the annual interest from both the investments is Rs. 144. Find each part.
Solution: Let the amount lent at 3% rate be Rs.X, then amount lent at 5% rate is 4000-X
So, 3% of X + 5% of (4000-X) = 144
5% of 4000 – 2% of X = 144
200 – 2% of X = 144
2% of X = 56
X = (56/2)×100
X = 2800
And 4000 -X = 1200.
How to solve this Question by Alligation Method
First we will calculate net rate of interest for Rs. 144 on 4000
So, net rate = (144/4000)× 100 = 3.6%
Other Important Subject Links
|एमपीएससी भारतातील बेरोजगारी आणि दारिद्रय 2021- Unemployment and Poverty in India for MPSC in Marathi|