Linear Independence and Linear Dependence
The set of vectors S = {x1, x2, …, xn} in a vector space V is said to be linearly independent provided that the equation
c1x1 + c2x2 + … + cnxn = 0
has only the trivial solution c1 = c2 = … = cn = 0
Example-1: The standard unit vectors in ℜn, viz.,
are linearly independent.
Note:
Any subset of a linearly independent set is a linearly independent set.
The coefficients in a linear combination of the vectors in a linearly independent set are unique.
A set of vectors is called linearly dependent if it is not linearly independent.
Example-2: The vectors u = (1, -1, 0), v = (1, 3, -1), and w = (5, 3, -2) are linearly dependent since 3u + 2v - w = 0.
Exercise: Determine whether the following vectors in ℜ4 are linearly dependent or independent.
(1, 3, -1, 4), (3, 8, -5, 7), (2, 9, 4, 23).
The vectors x1, x2, …, xn are linearly dependent if and only if at least one of them is a linear combination of the others.
Theorem: The n vectors x1, x2, …, xn in ℜn are linearly independent if and only if the n x n matrix
A=[x1 x2 … xn]
with the vectors as columns has nonzero determinant.
Theorem: Consider k vectors in ℜn, with k < n. Let
A=[x1, x2, …, xk]
be the n × k matrix having the k vectors as columns. Then the vectors x1, x2, …, xk are linearly independent if and only if some k × k submatrix of A has nonzero determinant.
A finite set S of vectors in a vector space V is called a basis for V provided that
- The vectors in S are linearly independent;
- The vectors in S span V.
Example-3: The set of standard unit vectors in ℜn, viz.,
form the standard basis for ℜn.
Note: Any set of n linearly independent vectors in ℜn is a basis for ℜn.
Example-4: u = (-2, 1, 0, 0) and v = (1, 0, 1, 1) is a basis of the solution space of the homogeneous system given in Example 3. The dimension of the solution space is 2.
Theorem: Let S = {x1, x2, …, xn} be a basis for the vector space V. Then any set of more than n vectors in V is linearly dependent.
Theorem: Any two bases of a vector space consist of the same number of vectors.
A vector space V is called finite dimensional if it has a basis consisting of a finite number of vectors. The unique number of vectors in each basis for V is called the dimension of V and is denoted by dim(V).
A vector space that is not finite dimensional is called infinite-dimensional.
Let be a matrix. The row vectors of A are the m vectors in ℜn given by
The subspace of ℜn spanned by the m row vectors r1, r2, .., rm is called the row space of the matrix A and is denoted by Row(A).
The dimension of the row space Row(A) is called the row rank of the matrix A.
Theorem: The nonzero row vectors of an echelon matrix are linearly independent and therefore form a basis for its row space Row(A).
Theorem: If two matrices are equivalent, then they have the same row space.
Note: To find a basis for the row space of a matrix, reduce the matrix to echelon form. Then the nonzero row vectors of the echelon matrix form a basis for the row space.
Let be a matrix. The column vectors of A are the n vectors in ℜm given by
The subspace of ℜm spanned by the n column vectors c1, c2, …, cn is called the column space of the matrix A and is denoted by Col(A).
The dimension of the row space Col(A) is called the column rank of the matrix A.
Note: To find a basis for the column space of a given matrix, reduce the matrix to echelon form. Then the column vectors of the given matrix that correspond to the pivot columns of the echelon matrix form a basis for the column space.
Exercise: Find a basis for the row space of the following matrix and state the dimension (row rank) of the row space. Also find a basis for the column space of the given matrix and state the dimension (column rank) of the column space.
Theorem: The row rank and the column rank of any matrix are equal.
The common value of the row rank and column rank of a matrix is called the rank of the matrix.
The solution space of the homogeneous system Ax = 0 is called the null space of A, denoted by Null(A)
Note:
- If A is an m x n matrix, then Null(A) and Row(A) are subspaces of ℜn, whereas
Col(A) is a subspace of ℜm. - rank(A) + dim Null(A) = n.
Application: Consider a homogeneous system of m linear equations in n unknowns (m ≤ n). If the m × n coefficient matrix has rank r, (so r out of the m equations are irredundant), the system has n - r linearly independent solutions.
Theorem: The nonhomogeneous linear system Ax = b is consistent if and only if the vector b is in the column space of A.
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