We have the quadratic polynomial p(x) = kx² + 2x + 3k.
The sum of the zeros is -b/a, which in this case is -2/ k. The product of the zeros is c/a, which is 3k/k = 3.
According to the problem, the sum of the zeros is equal to their product. Therefore, we have:
-2/k = 3
To solve for k, we can cross-multiply and solve the resulting equation:
-2 = 3k
Dividing both sides by 3:
k = -2/3
Therefore, the value of k that satisfies the condition where the sum of the zeros is equal to their product in the given quadratic polynomial p(x) = kx² + 2x + 3k is k = -2/3.
If the sum of zeros of the quadratic poynomial p(x)=kx²+2x+3k is equal to their product, then the value of k = -2/3.
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