In which one of the following reactions the maximum quantity of H2 gas is produced by the decomposition of 1 g of the compound by H2O/O2?

Maximum Quantity of H2 gas is Produced By Decomposition

In the below-mentioned equations, we have explained the maximum quantity of H2 (Hydrogen gas) is produced by decompositions of 1g.

In equation 1

CH4 + H2O → CO + 3H2 we get

(12 + 4 = 16) gm + 1 gm = 6 gm

As16 gm produces 6 gm of H2

Hence 1 gm produces 6/16 = 0.375 gm of H2

In equation 2

CO + H2O → CO2 + H2

(12 + 16 = 28) gm + 1 gm = 2 gm

As 28 gm produces 2 gm of H2

Hence 1 gm will produce 2/28 = 0.0714 gm of H2

In equation 3

CH4 + ½ O2 → CO + 2H2

(12 + 4 = 16) gm + 1 gm = 4 gm of H2

As 16 gm produces 4gm of H2

Hence 1 gm will produce 4/16 = 0.25 gm of H2

In equation 4

C12H24 + 6O2 → 12CO + 12H2

(144 + 24 = 168) gm + 1 gm = 24 gm of H2

As 168 gm produces 24 gm of H2

Hence 1 gm will produce 24/168 = 0.142 gm of H2

Summary:

In which one of the following reactions the maximum quantity of H2 gas is produced by the decomposition of 1 g of the compound by H2O/O2? (I) CH₄ + H₂O → CO + 3H₂ (II) CO + H₂O → CO₂ + H₂ (III) CH₄ + ½ O₂ → CO + 2H₂ (IV) C₁₂H₂₄ + 6O₂ → 12CO + 12H₂

In CH4 + H2O → CO + 3H2, the maximum quantity of H2 gas is produced by the decomposition of 1 g of a compound by H2O/O2. In this chemical equation, Methane and Water react with each other and create carbon monoxide and Pentylbenzene.