If x=2/3 and x=−3 are the Roots of the Quadratic Equation ax²+7x+b=0 then Find the Values of a and b
By BYJU'S Exam Prep
Updated on: October 17th, 2023
If x=2/3 and x=−3 are the roots of the quadratic equation ax²+7x+b=0 then find the values of a and b
To solve the given question and to find the values of a and b, we will use the given steps:
- Step 1: Use the given values to find out the exact polynomial: x=2/3 and x=−3
- Step 2: Solve the resulted equation
- Step 3: Compare with the given polynomial ax²+7x+b=0 and find out the values of a and b
Table of content
If x=2/3 and x=−3 are the Roots of the Quadratic Equation ax²+7x+b=0 then Find the Values of a and b.
Solution:
As given, x=2/3, and x=−3 are roots of the equation ax²+7x+b=0 then
We can use these to find the exact polynomial in the following way: (x−2/3)(x−(−3)=0
On expanding, we will get:
⇒x²−(2/3)x+3x−2=0
⇒x²+(7/3)x−2=0
⇒3x²+7x−6=0
Now we will compare with the given polynomial with two unknown variables: ax²+7x+b=0
Therefore, we will get a=3, b=−6
If x=2/3 and x=−3 are the Roots of the Quadratic Equation ax²+7x+b=0 then the Values of a = 3, and b = −6
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