If α and β are the Zeroes of the Quadratic Polynomial p(x) = x^2– x – 2, Find a Polynomial Whose Zeroes are 2α + 1 and 2β + 1
By BYJU'S Exam Prep
Updated on: October 17th, 2023
If α and β are the Zeroes of the Quadratic Polynomial p(x) = x2– x – 2, Find a Polynomial Whose Zeroes are 2α + 1 and 2β + 1
Here are the steps to find out the polynomial
Step 1: Determine the values of α and β by solving the quadratic equation p(x) = 0.
Step 2: Solve the quadratic equation to find the values of α and β.
Step 3: Express and Form the polynomial with the new zeroes.
Table of content
If α and β are the Zeroes of the Quadratic Polynomial p(x) = x2– x – 2, Find a Polynomial Whose Zeroes are 2α + 1 and 2β + 1
Solution:
Given that α and β are the zeroes of the quadratic polynomial p(x) = x2– x – 2, we can find the sum and product of the zeroes using the Vieta’s formulas.
The sum of the zeroes is α + β = -(-1)/1 = 1, and the product of the zeroes is αβ = -2/1 = -2.
Now, let’s find the polynomial with zeroes 2α + 1 and 2β + 1.
The sum of the new zeroes is (2α + 1) + (2β + 1) = 2(α + β) + 2 = 2(1) + 2 = 4.
The product of the new zeroes is (2α + 1)(2β + 1) = 2(αβ) + 2(α) + 2(β) + 1 = 2(-2) + 2(α) + 2(β) + 1 = -4 + 2α + 2β + 1 = 2α + 2β – 3.
Therefore, the polynomial with zeroes 2α + 1 and 2β + 1 is q(x) = x2 – (sum of the zeroes)x + product of the zeroes.
Substituting the values, we have q(x) = x2– 4x – 5.
So, the polynomial with zeroes 2α + 1 and 2β + 1 is indeed q(x) = x2 – 4x – 5.
Answer:
If α and β are the Zeroes of the Quadratic Polynomial p(x) = x2– x – 2, then a Polynomial Whose Zeroes are 2α + 1 and 2β + 1 is q(x) = x^2 – 4x – 5
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