For What Value of k, (-4) is a Zero of the Polynomial x²-x-(2k+2)
By BYJU'S Exam Prep
Updated on: October 17th, 2023
k=9. We can find the value of k by using the below mentioned steps.
Here are the steps in detail:
- Start with the polynomial and substitute -4 into the polynomial
- Simplify the expression inside the parentheses and combine like terms.
- Set the expression equal to zero, since -4 is a zero of the polynomial and solve for k by isolating it on one side of the equation
Table of content
For What Value of k, (-4) is a Zero of the Polynomial x²-x-(2k+2)
Solution:
To find the value of k for which -4 is a zero of the polynomial x²-x-(2k+2), we can substitute -4 into the polynomial and solve for k.
Substituting -4 into the polynomial, we get: (-4)²-(-4)-(2k+2)=0
Simplifying:
16+4-2k-2=0
20-2k-2=0
18-2k=0
Now, let’s solve for k:
18-2k=0
-2k=-18
2k = 18
k=9
Therefore, the value of k for which -4 is a zero of the polynomial x²-x-(2k+2) is k=9.
Answer:
The Value of k is 9 so that -4 is a Zero of the Polynomial x²-x-(2k+2)
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