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For What Value of k, (-4) is a Zero of the Polynomial x²-x-(2k+2)

By BYJU'S Exam Prep

Updated on: October 17th, 2023

k=9. We can find the value of k by using the below mentioned steps.

Here are the steps in detail:

  • Start with the polynomial and substitute -4 into the polynomial
  • Simplify the expression inside the parentheses and combine like terms.
  • Set the expression equal to zero, since -4 is a zero of the polynomial and solve for k by isolating it on one side of the equation

For What Value of k, (-4) is a Zero of the Polynomial x²-x-(2k+2)

Solution:

To find the value of k for which -4 is a zero of the polynomial x²-x-(2k+2), we can substitute -4 into the polynomial and solve for k.

Substituting -4 into the polynomial, we get: (-4)²-(-4)-(2k+2)=0

Simplifying:

16+4-2k-2=0

20-2k-2=0

18-2k=0

Now, let’s solve for k:

18-2k=0

-2k=-18

2k = 18

k=9

Therefore, the value of k for which -4 is a zero of the polynomial x²-x-(2k+2) is k=9.

Answer:

The Value of k is 9 so that -4 is a Zero of the Polynomial x²-x-(2k+2)

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