- Home/
- GATE ELECTRICAL/
- GATE EE/
- Article
If a Transformer have Turn Ratio 5
By BYJU'S Exam Prep
Updated on: September 25th, 2023
If a transformer have turn ratio 5, frequency 50 Hz, root mean square value of potential difference on primary winding is 100 volts and the resistance of the secondary winding is 500 then the peak value of voltage in secondary winding will be (the efficiency of the transformer is hundred percent)-
- 500√2 volts
- 50√2 volts
- 10√2 volts
- 40√2 volts
Answer: A. 500√2 volts
If a transform turn ratio is 5, then the value of voltage is 500√2 volts.
Solution
Transformer turn ratio K=5.
Root mean square value of induced voltage E1,rms=100 volts,
Root mean square vale of secondary winding =E2,rms
Transformer voltage (or) turns ratio K=E1,rms/E2,rms
So, E2,rms=k.E1,rms
E2,rms=5×100
E2,rms=500 volts
Then, peak value of secondary voltage E2,peak=√2×E2,rms
E2,peak=√2×500
E2,peak=500√2 volts.
☛ Related Questions: