# Norton Current is Determined as

By BYJU'S Exam Prep

Updated on: September 25th, 2023

### Determine Norton current IN at terminals A, and B for the circuit consisting of VS, R1, R2, and R3 shown in the given circuit.

1. 676 mA
2. 244 mA
3. 431 mA
4. 75 mA
• Answer: B. 244 mA

Solution:

Norton’s theorem states that a linear two-terminal circuit can be replaced by an equivalent circuit which consists of a Norton equivalent current source IN in parallel with a Norton equivalent resistor of resistance RN.

Here IN is the short circuit current through the terminals, RN is the equivalent resistance seen from the terminals when independent sources are turned off.

For the circuit given in the problem, we need to construct Norton equivalent circuit at terminals A and B.

Finding IN:

As we have discussed, IN is the short circuit current through terminals A and B. We need to short circuit terminals A and B.

First, we need to find node Voltage V, which is shown in the above figure.

Applying KCL at node gives,

(V-75)/68+V/68+V/120=0

(V-75)120+120V+68V=0

308×V=75×120

V=(75×120)/308

Then IN=V/120 =[(75×120)/308×120]=243.506 mAmps≈244 mAmps.

## Norton’s current IN at terminals A, and B for the given circuit is 244 mA.

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