If Power Dissipated in the 9 Ohm Resistor

Answer: D. 10 V

If power dissipated in the 9 Ohm resistor in the circuit shown is 36 Watt, the potential difference across the 2 Ohm resistors is 10 V.

Solution:

Given that,

The power dissipated in the 9 Ohm resistor is 36 W.

⇒P=I²R=36

⇒P=I²(9)=36

⇒I=2 A

If I_T is the total current delivered by the voltage source, From the current division technique,

2=I_T(6)/(6+9)

I_T=30/6=5 A

The same current flows through the 2 Ohm resistor,

The potential drop across the 2-Ohm resistor = 2×5=10 V

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