CSIR NET Chemical Science Formula Sheet: During the preparation, the candidates study different formulas to solve problems, but at the last moment, these formulas might not be remembered by the candidates due to exam fear or pressure. We at BYJU'S Exam Prep do not want our students to lag anywhere during the preparation, so we have come up with a concept of a Formula Sheet that will help them revise the important formulas at the last moment. This formula sheet will be a short revision tool and contain only important formulas that need to be studied at the last minute to boost the score. Our experienced subject-matter experts have meticulously designed this CSIR NET Chemical Science Formula Sheet to provide you with the best authentic material.
In this article, we will cover the CSIR NET Chemical Science Most Important Formulas of Solutions. Aspiring candidates can check all the most important Chemical Science formulas of Solutions and download the PDF for the last minute revision. Read the full article to know about the benefits of the formula sheet and how to use it effectively.
Most Important Formulas of Solutions (Download PDF)
A solution is defined as a homogeneous mixture of two or more substances having uniform properties throughout. Since it is a homogeneous mixture, the solution constitutes a single phase. The substances of which the solution is made are called its components. The solute is the component present in a smaller proportion that dissolves to form the solution. The solvent, on the other hand, is the component present in a larger proportion in which the solute dissolves.
Suppose there is a binary solution consists of nA moles of a volatile liquid A and nB moles of a volatile liquid B. If pA and pB are partial pressures of the two liquid components, then, according to the Raoult’s law,
pA = xA pA° and pB = xBpB°
Here, xA is the mole fraction of the component A given by nA/ (nA + nB), xB is the mole fraction of the component B given by nB/ (nA + nB) and pA° and pB° are the vapour pressures of pure components A and B, respectively.
If the vapour behaves like an ideal gas, then, according to Dalton’s law of partial pressures, the total vapour pressure P is given by:
P = pA + pB = xApA° + xBpB°
In general, Raoult’s law may be expressed as
pi = xipi°
and the total vapour pressure may be expressed as
P = Σpi
Total Vapour Pressure in Terms of Mole Fractions of the Component in Vapour Phase.
Chemical Potentials of Ideal and Non-ideal Solutions
For an ideal solution, ai = xi.
The mass of a gas dissolved per unit volume of a solvent is directly related to the pressure of the gas in equilibrium with the solution at constant temperature.
If m is the mass of a gas dissolved per unit volume of a solvent and P is the pressure of the gas in equilibrium with the solution, then, at constant temperature,
m ∝ P or m = kP
Here, k is the proportionality constant.
Vapour Pressure Lowering:
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