Important Questions for CSIR NET Chemical Science - Physical Chemistry-Part V

By Renuka Miglani|Updated : April 26th, 2022

Are you preparing for CSIR-NET 2022 and looking for some short and authentic study notes for Chemical Sciences to smoothen your preparation journey? We have got you covered!

Candidates preparing for their upcoming CSIR NET 2022 exam can really make their preparation journey easier with the help of some reliable study notes that cover the topics in the most simple way. We at BYJU'S Exam Prep have come up with the idea of providing Topic Wise Important Questions on Physical Chemistry-Part V in the Chemical Science syllabus. 

The important questions on Physical Chemistry-Part V are developed by our experienced subject-matter experts to provide you with the most standard and authentic set of study materials to be focused upon. The students need the best resources for their preparation to clear the CSIR NET 2022 examination, Here are the most reliable important questions to make the topics easier for you and also help you to save your time to do preparations for the upcoming CSIR-NET 2022 exam.

Most Important Questions Physical Chemistry-Part V

1. 

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k1 = 4 s-1

k2 = 6 s-1

Calculate the relaxation time given that equilibrium concentration of A is 0.4 M and the initial concentration of A is 1M.

  1. 0.064
  2. 0.032
  3. 0.071
  4. 0.059

2. Calculate the vibrational degree of freedom for Anthracene molecule.

  1. 66
  2. 23
  3. 60
  4. 50

3. 1× 10-6 moles of the enzymes carbonic anhydrase dehydrate H2CO3 and produces 0.6 mol of CO2 per second. Calculate the turnover number of the enzyme.

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4. It is given that sodium contains 2g of anhydrous BaCl2 in 4000 c.c of water and has a specific conductivity of 0.0058 ohm–1. Calculate the molecular conductivity of this solution.

  1. 240 ohm–1 c.c.
  2. 24.1 ohm–1 c.c.
  3. 2.41 ohm–1 c.c.
  4. 2410 ohm–1 c.c.

5. Maximum degree of freedom for a two-component system is:

  1. 5
  2. 1
  3. 2
  4. 3

6. In what condition the real gas equation follows an ideal gas equation?

  1. high pressure, high temperature, and low density
  2. low pressure, high temperature, and low density
  3. low pressure, low temperature, and low density
  4. low pressure, high temperature, and high density

7. Phosphorus pentachloride, PCl5 is a trigonal bipyramidal molecule. To what point group does it belong?

  1. D3v
  2. D3h
  3. C3h
  4. D5h

8. If the difference between 2 maxima in the vibrational rotational spectrum is 360 cm-1, then what will be the value of Jmax If B= 10 cm-1 under rigid rotor approximation? 

  1. 1
  2. 8
  3. 10
  4. 12 

9. A particle in a 1-D box of length 1.20 Å. The wavelength associated with it in its ground state is

  1. 2.4 nm
  2. 0.24 nm
  3. 24 nm
  4. 0.024 nm

10. Which of the following is the correct statement about amorphous Solid?

  1. The constituent particle is arranged in a regular fashion.
  2. Regular Shape
  3. They are Isotropic
  4. They have a Sharp melting point

Answer Key:

  1. A
  2. A
  3. A
  4. D
  5. D
  6. B
  7. B
  8. B
  9. B
  10. C

Solutions:

Solution 1.

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Solution 2.

The structure of anthracene is: 

Vibrational degree of freedom = (3N - 6)

N = 24

Vibrational degree of freedom = 3(24) – 6

= 66

Solution 3.

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Solution 4.

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Solution 5.

From Gibbs phase rule:

F = C – P + 2

 Here, no. of component = 2

 For maximum F, phase should be minimum, therefore, P = 1

 Fmax. = -1 + 2 + 2

 Fmax. = 3

 Maximum degree of freedom for 2 component system = 3

Solution 6.

Generally, a gas behaves more like an ideal gas at higher temperature and lower pressure. Since, at high temperature and low pressure, the gas expands enormously which results in an increase in volume, but mass remains the same. Hence, a gas should be of low density.

Solution 7.

PCl5 has trigonal bipyramidal molecular geometry and it contains a C3 main rotation axis and 3 perpendicular C2 axes. There are 3 σv planes and a σh plane. Hence PCl5 belongs to the D3h point group.

Solution 8.

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Solution 9.

Wavelength associated with a particle in 1-D box = 2L/n

= (2×1.20)/1 = 2.4 Å

=2.4×10-10 m

=0.24 nm

Solution 10.

An amorphous solid is anyone-glasslike solid that doesn't arrange the atoms and particles in a positive cross-section pattern. There are plastic, glass, and gel solids. Amorphous solids are isotropic. That is, they exhibit uniform properties in all directions. The thermal and electrical conductivities, coefficient of thermal expansion and refractive index of an amorphous solid have the same value in whatever direction the properties are measured.

Properties of Amorphous Solids are:

  1. Absence of Long - Range Order
  2. No Sharp Melting Point
  3. Conversion into a Glasslike Form

 

 

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