Important Questions for Chemical Science Students - Data Analysis

By Astha Singh|Updated : February 2nd, 2022

Hello Aspirants,

It will not be a new thing for you if we say that BYJU'S Exam Prep is considered the synonym for success. For the past 5 years, At BYJU'S Exam Prep, we have been promoting talented candidates of the CSIR-NET category to the path of success. As a result, BYJU'S Exam Prep has been an integral part of the preparation journey of many Aspirants.

As we all know, the CSIR-NET exam is very near, and there is no time left for revision. At this point, you must be seeking some ready-made authentic short revision notes or some important questions to practice just before the exam. How will you react if you get all these study materials in one place? It will be beneficial for you at this time, right! At BYJU'S Exam Prep, we come up with the Important Questions on Data Analysis for Chemical Sciences to help you score good marks, which our experienced Exam experts have meticulously designed.

So what are you waiting for? Scroll down the article below and start studying for the CSIR NET Exam; these questions will be fruitful during last-minute revision to fetch more marks in the exams. Students can also download it as a PDF file and save it for future purposes.

Most Important Questions on Data Analysis (Download PDF)

 Important Questions on Data Analysis

  1. 3 groups of students perform a weight measuring experiment to give a result. Group 1, Group 2, and Group 3 report 10, 10.1 and 10.5 g of the sample respectively. The actual weight of the sample is 10.6 g. Which group’s result is more accurate?
  1. Group 1
  2. Group 1
  3. Group 1
  4. All are equally accurate
  1. The closeness of a measurement to the true value is defined as:
  1. Accuracy
  2.  Precision
  3. Approx
  4. Estimate 
  1. When a measurement is repeatable and consistent, it is said to have...
  1. High precision 
  2. Low precision
  3. High accuracy
  4. Low accuracy
  1. During the gravimetric analysis Nickel was measured as 0.03g and the actual amount of Nickel present in the complex is 0.04 g, Calculate the relative error.
  1. 0.25
  2. –0.205
  3. –0.25
  4. –0.025
  1. What will be the error in the result if the titrant has an uncertainty of ±5% and the titrant has an uncertainty of ±1%?
  1. 5.09%
  2. 5.9%
  3. 6.09%
  4. 7.09%
  1. Calculate the mode from the following data

2, 1, 12, 41, 2, 1, 2, 2, 5

  1. 2
  2. 1
  3. 5
  4. 41
  1. During the acid-base titration, a student has the following endpoints.

10.1, 10.2, 10.1, 10.4, 10.6

Calculate the mean of the experiment.

  1. 10.28
  2. 10.45
  3. 10.39
  4. 10.30
  1. What is the average deviation from the following data?

10, 15, 20, 25, 30

  1. 3
  2. 4
  3. 5
  4. 6
  1. Calculate the standard deviation.

1.2, 2.4, 3.6

  1. 1.2
  2. 2.4
  3. 2.2
  4. 3.0
  1. From the Gaussian distribution curve represented as byjusexamprep. Calculate the avg. value.
  1. 5  
  2. 6
  3. 7
  4. 4

Answer Key:

  1. C
  2. A
  3. A
  4. C
  5. A
  6. A
  7. A
  8. D
  9. A
  10. A

Solutions:

Solution 1. Accuracy is the degree to which the result of a measurement, calculation, or specification conforms to the correct value.

Therefore, the Group 3 group result is more accurate because 10.5 g is closer to 10.6 g.

Solution 2. Accuracy is the degree to which the result of a measurement, calculation, or specification conforms to the correct value. Closeness to true value is defined by accuracy. 

Solution 3. If the experiment is repeated to produce the same value, then it is defined by the term precision because repeating of the same value doesn’t mean it is accurate. It can be repeated via having a random error that cannot be overcome. 

byjusexamprep

Solution 6. Mode is defined as a value that occurs most frequently in a dataset.

Here 2 repeated 3 times maximum among the other data. Hence, 2 is the correct answer.

 byjusexamprep= 10.28

Solution 8. First calculate the mean = byjusexamprep

byjusexamprep

Solution 9. S → Standard deviation

byjusexamprep

Solution 10.

byjusexamprep

From the Gaussian distribution curve, we know avg. value is the maximum value of e–y

To get maximum value, put y = 0

3x – 15 = 0

3x = 15

x = 5

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