By Renuka Miglani|Updated : January 19th, 2022

Hello Aspirants,

It will not be a new thing for you if we say that BYJU'S Exam Prep is considered as the synonym for success. For the past 5 years, At BYJU'S Exam Prep we have been promoting talented candidates of the CSIR-NET category to the path of success. BYJU'S Exam Prep has been an integral part of the preparation journey of many Aspirants.

As we all know, the CSIR-NET exam is very near and there is no time left for revision. At this point in time, you must be seeking some ready-made authentic short revision notes or some important questions to practice just before the exam. How will you react if you get all these study materials in one place? It will be beneficial for you at this time right! We at BYJU'S Exam Prep come up with the Most Important Questions on Compound Interest for General Aptitude to help you score good marks which have been meticulously designed by our experienced subject-matter experts.

So what are you waiting for? Scroll down the article below and start studying for the CSIR NET Exam, these questions will be fruitful during last-minute revision to fetch more marks in the exams. Students can also download it as a PDF file and save it for future purposes.

1. A certain sum borrowed and paid in two annual instalments of Rs. 2227 and Rs. 2023 respectively. If the rate of compound interest is 19% per annum, then find the sum borrowed.

1. Rs 3300
2. Rs 4000
3. Rs 3800
4. Rs 4200

2. Arun saves Rs. 4500 at the end of each year and invests at a compound interest rate of 8% per annum. How much amount will he have at end of 3 years?

1. Rs 14608.8
2. Rs 14580
3. Rs 14997.6
4. Rs 13500

3. The difference of compound interest and simple interest for 3 years and for 2 years are in ratio 19: 6. Find the rate of interest per annum (in %). 4. The difference between compound interest and simple interest on a sum for 2 years at 20% per annum, when it is compounded annually is Rs. 64. If the interest is compounded half-yearly, then the difference in two interests would be how much approximately?

1. Rs. 175
2. Rs. 160
3. Rs. 145
4. Rs. 154

5. If the difference between the compound interest and simple interest at on a certain sum at the rate of 5% per annum for 2 years is Rs. 225, find the principle.

A. Rs. 75,000

B. Rs. 80,000

C. Rs. 85,000

D. Rs. 90,000

1. (D)
2. (B)
3. (C)
4. (A)

6. There is a 40% increase in an amount in 4 years at simple interest. What will be the compound interest on Rs. 6000 after 3 years at the same rate?

1. Rs. 1260
2. Rs. 1986
3. Rs. 19860
4. Rs. 7986

7. What is the difference between the maturity values, if Rs. 12,500 is invested for 2 years at 20% per annum simple interest and compound interest?

1. Rs. 750
2. Rs. 650
3. Rs. 550
4. Rs. 500

8. A woman invests Rs. 2000 at the start of each year at 5% compound interest per annum. How much will her investments be at the end of the 2nd year?

1. Rs. 2205
2. Rs. 4305
3. Rs. 2355
4. Rs. 4350

9. An amount is deposited at 8% p.a. compound interest. If the first-year interest is Rs. 72, find the interest amount for the 2nd year.

1. Rs. 77.56
2. Rs. 77.64
3. Rs. 77.76
4. Rs. 85.77

10. If the amount is 2.25 times of the sum after 2 years at compound interest (compound annually) then calculate the rate of interest per annum?

1. 25%
2. 30%
3. 45%
4. 50%

### SOLUTIONS

Solution 1 -

We know that:

If each instalment is I1 and I2,

Then, Total sum = Now, according to question,

The total sum borrowed = = 1871.43 + 1428.57

= 3300 Rs.

Therefore, the total sum which was borrowed = 3300 Rs.

Alternate method:

For the second year, principal =

= 1871.43 + 1428.57

= 3300 Rs.

Therefore, total sum which was borrowed = 3300 Rs.

Alternate method:

For the second year, principal = Therefore, total sum which was borrowed = 3300 Rs.

Solution 2 -

We know that: Solution 3 - Solution 4 -

As we know that Difference(d)= (p×r2)/10000 for 2-year period.

∴ (p×102)/10000 = 64

⇒ p = Rs. 6400

For half-yearly, r=20/2 =10% and t=2×2 = 4 year

∴ ATQ,

= [6400{1+(10/100)4} – 6400]- [6400{1+(20/100)}2 – 6400]

= {6400*(14641/10000)- 6400} - {6400*(36/25)- 6400}

= (234256/25) - (64×36×4)

= 9370.24 – 9216 = Rs. 154 (approx.)

Solution 5 -

Let the principle =100

%Rate=5% CI -SI= 0.25=225(Given)

Then 1=900 & 100= 90,000 = Required principle  Solution 6:  Solution 7: Solution 8: Solution 9:

Interest for the second year = 72 + 8% of 72 = Rs 77.76

Solution 10: ### More from us:

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