CSIR-NET Chemical Science: Most Important Questions of Chemical Bonding!!!

By Neetesh Tiwari|Updated : August 4th, 2021

Hello Gradians,

It will not be a new thing for you if we say that Gradeup is considered the synonym for success. For the past 5 years, At BYJU'S Exam Prep, we have been promoting talented candidates of the CSIR-NET category to the path of success. As a result, BYJU'S Exam Prep has been an integral part of the preparation journey of many Aspirants.

As we all know, the CSIR-NET exam is very near, and there is no time left for revision. At this point, you must be seeking some ready-made authentic short revision notes or some important questions to practice just before the exam. How will you react if you get all these study materials in one place? It will be beneficial for you at this time, right! We at BYJU'S Exam Prep comes up with Important Questions on Chemical Bonding for Chemical Sciences to help you score good marks, which our experienced subject-matter experts have meticulously designed. So what are you waiting for? Scroll down the article below and start study for the CSIR NET Exam; these questions will be fruitful during last-minute revision to fetch more marks in the exams. Students can also download it as a PDF file and save it for future purposes.

We have been providing short study notes for the Chemical Science subject, which can be checked here. We have experienced immense love and support from all of you through these short notes in the CSIR-NET category, and we hope you all continue to support us in the same way!

Hello Gradians,

It will not be a new thing for you if we say that Gradeup is considered the synonym for success. For the past 5 years, At BYJU'S Exam Prep, we have been promoting talented candidates of the CSIR-NET category to the path of success. As a result, BYJU'S Exam Prep has been an integral part of the preparation journey of many Aspirants.

As we all know, the CSIR-NET exam is very near, and there is no time left for revision. At this point, you must be seeking some ready-made authentic short revision notes or some important questions to practice just before the exam. How will you react if you get all these study materials in one place? It will be beneficial for you at this time, right! We at BYJU'S Exam Prep comes up with Important Questions on Chemical Bonding for Chemical Sciences to help you score good marks, which our experienced subject-matter experts have meticulously designed. So what are you waiting for? Scroll down the article below and start study for the CSIR NET Exam; these questions will be fruitful during last-minute revision to fetch more marks in the exams. Students can also download it as a PDF file and save it for future purposes.

We have been providing short study notes for the Chemical Science subject, which can be checked here. We have experienced immense love and support from all of you through these short notes in the CSIR-NET category, and we hope you all continue to support us in the same way!

Important Questions on Chemical Bonding

1. Predict the shape of PCl4+ ion using VSEPR theory.

  1. Trigonal planar
  2. Bent
  3. Tetrahedral
  4. Pyramidal

2. Predict the shape of the XeF2 molecule.

  1. Linear
  2. Bent
  3. Trigonal bipyramidal
  4. Square planar

3. The correct order of O-O bond length in O2,  H2O2 and O3 is:

  1. O2>O3>H2O2
  2. H2O2>O3>O2
  3. O3>O2> H2O2
  4. O3>H2O2>O2

4. The formation of molecular orbitals from atomic orbitals causes electron density to be

  1. Zero in nodal plane
  2. Zero in the surface of the lobe
  3. Minimum in nodal plane
  4. Maximum in nodal plane

5. Incorrect order of bond length is:

  1. CO < CO+
  2. NO > NO+
  3. N2+ < N2
  4. H2+<H2

 6. Order of increasing stability is:

  1. N22- < N2- = N2+ < N2
  2. N22- < N2- < N2+ < N2
  3. N22- = N2+ < N2- < N2
  4. N22- < N2+< N2- < N2

7. The paramagnetic species are:

  1. KO2
  2. SiO2
  3. TiO2
  4. BaO2

8. The main axis of a diatomic molecule is Z. The orbitals Px and Py overlap to form

  1. - molecular orbital
  2. – molecular orbital
  3. 𝛿 - molecular orbital
  4. No bond is formed.

9. How many nodal surfaces can be present in the molecular orbital formed by the overlap of s and px (x-axis is the molecular axis)?

  1. 1
  2. 2
  3. 3
  4. None of the above

10. The dipole moment of certain diatomic molecule X – Y is 0.38 D . If the X – Y distance is 158 pm, the percentage of electronic charge developed on X-atoms is:

  1. 4
  2. 5
  3. 6
  4. 2

Answer Keys

 

  1. C
  2. A
  3. B
  4. A
  5. A
  6. A
  7. A
  8. D
  9. B
  10. B

 Solutions

 

Solution 1: 

P contains five valence electrons. Out of these five electrons, four will be used in bonding with four Cl atoms. There is a positive charge which indicates the removal of one electron. In this, there is no lone pair. So, its shape is tetrahedral.

Solution 2: 

 XeF2= 1/2(8+2) =5

As 2 F are present, they will be used in bonding. There will be three lone pairs that will occupy equatorial positions.

So, it is linear in shape.

Solution 3: 

 

Solution 4:

When electrons are present in bonding orbitals, they spend most of the time between the nuclei of two atoms while when they are present in antibonding orbitals, they spend their time outside the nucleus. This is because there is an increase in electron density in bonding and a decrease in electron density in antibonding. The amplitude of the wave function is zero, and hence the probability of finding an electron in the region.

Solution 5:

 The Molecular orbital configuration of CO is:

Removal of one electron from CO will result in an increase in bond order. Hence, the bond order of CO < CO+
Therefore, the bond length order will be: 

CO > CO+.

Solution 6:

The order of stability is directly proportional to the bond order. Therefore, the correct order of stability is N22- < N2 = N2+ < N2

Solution 7:

 KO2→K+ + O2- =17e- in valence shell so unpaired electron present and shows paramagnetism.
Rest all have O22- dioxide ion in which all the electrons are paired and diamagnetic.

Solution 8:

No bond is formed as no overlap is possible between Px and Py.

Solution 9:

 

Solution 10:

 

% Electron charge is:

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Neetesh TiwariNeetesh TiwariMember since Aug 2020
Working Experience of more than 2 years in Education Industry. Currently associated to CSIR-NET at Gradeup. Guiding students to crack the exam and fulfil their dreams.
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