CSIR NET Chemical Science: Most Important Questions of Inorganic Chemistry!!! (Download PDF)

Inorganic Chemistry - Most Important Questions

1. It is given that D(H-H) and D(F-F) in H₂ and F₂ are 436 and 158 kJ/mol, calculate the bond dissociation enthalpy of HF (in kJ/mol).

1. 250
2. 297
3. 300
4. 350

2. [NO₃]- has D₃h symmetry. Predict its structure.

1. Planar
2. Non-planar
3. cannot predict.
4. None of the above

3. Predict the structure of [NO₂]+ ion using the VSEPR theory.

1. Bent
2. Linear
3. Pyramidal
4. Planar

4. The structure of unit cell for sodium chloride is consistent with:

1. NaCl
2. Na₂Cl
3. NaCl₂
4. Not fixed

5. Identify the mixture of solvents in which intermolecular hydrogen bonding will take place.

1. EtOH and H2O
2. Et2O and THF
3. EtNH₂ and Et₂O
4. None of the above

6. A cryptand is:

1. Monocyclic ligand
2. Bicyclic ligand
3. Polycyclic ligand
4. None of the above

7. The structure of the dimer of BeCl₂ is:

1. Trigonal planar
2. Linear
3. Tetrahedral
4. Bent

8. Thermal decomposition of magnesium carbonate takes place at:

1. 1173 K
2. 813 K
3. 1633 K
4. 1563 K

9. For sesquihydrate, n is:

1. 1/2
2. 3/2
3. 1
4. 5/2

10. How many cage isomers are possible for C₂B₄H₆?

1. 1
2. 2
3. 3
4. 4

Solutions 

Solution 1: Calculate bond dissociation enthalpy of HF as:

D(H-F) =1/2[D(H-H)+D(F-F)]

            =1/2(436+158)

            = 297

Solution 2: It is given that [NO3]- has D₃h symmetry which means it must be planar having bond angle of 1200 and distance between N-O will be equal.

Solution 3: N contains five valence electrons. If positive charge is allowed to localise on N, it will become N+ which indicates the presence of 4 valence electrons. O needs two electrons to complete its octet. All the 4 electrons of N will be used in bonding which results in formation of two double bonds. Due to absence of lone pairs on N, [NO2] +will be linear.

Solution 4: The number of sodium and chloride ions belongs to the unit cell are:

For both ions, the total is 4, so, the formula will be NaCl.

Solution 5: When H is bonded to more electronegative atoms like N, F or O, formation of hydrogen bonding takes place. Among the given options, intermolecular hydrogen bonding is possible only in option A.

Solution 6: A cryptand is considered as a polycyclic ligand in which cavity is present. When ligand is coordinated with a metal ion, the complex ion is known as cryptate.

Solution 7: Each Be atom has tendency to accommodate 8 electrons in its valence shell. In monomer of BeCl₂, only four valence electrons are associated with each Be atom due to which it can accept one or two lone pair of electrons. Each Cl atom contains three lone pair electrons. This arrangement gives BeCl₂ dimer trigonal planar shape.

Solution 8: Down the group, thermal stability increases because of decrease in polarizing power of cation. So, according to this, B is the correct option.

Solution 9: If the value of n is 3/2, it is known as sesquihydrate.

Solution 10:  C2B4H6 has a closed cage structure and it will adopt octahedron shape. In octahedron, all vertices are equal due to which means that two arrangements are possible which results in two cage isomers.

Answer keys:

1. B

2. A

3. B

4. A

5. A

6. C

7. A

8. B

9. B

10. B

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