CSIR-NET Chemical Science - INORGANIC CHEMISTRY MCQ - Attempt Here!

INORGANIC CHEMISTRY MCQ 

1. The correct order that describes the rate of exchange of water molecules between the coordination sphere and the bulk is

1. Cr³⁺ < Al³⁺ < Cr²⁺ < Ni²⁺
2. Cr3+ < Al3+ < Ni2+ < Cr2+
3. Cr3+ < Ni2+ < Cr2+ < Al3+
4. Cr3+ < Cr2+ < Al3+ < Ni2+

2. The main reason behind the red color of oxyhemoglobin is due to

1. d-d transition
2. Intraligand π – π* transition
3. Metal to ligand charge transfer transition
4. Ligand to metal charge transfer transition

3. The correct order of CO stretching frequency in the infrared spectra spectra of Anhydride, Amide and Ketone is

1. Anhydride> Amide> Ketone
2. Anhydride>Ketone>Amide
3. Ketone>Amide>Anhydride
4. Amide>Anhydride>Ketone

4. The initial rate r₀ of a certain reaction depends on the initial concentration of species A, B and C as shown in the table. (Concentration in mM and r₀ in mM s^–1)

1. 4
2. 3
3. 2
4. 1

5. For a heteronuclear diatomic molecule, if the bond length is greater in the upper vibrational state, the gap between the successive absorption lines of P-branch will:

1. Increases non-linearly
2. Increases linearly
3. Decreases non-linearly
4. Decreases linearly

6. Based on VSEPR theory, the structures of SbPh₅ and PPh₅ respectively are -

1. Trigonal bipyramidal, square pyramidal
2. Trigonal bipyramidal, trigonal bipyramidal
3. Square pyramidal, trigonal bipyramidal
4. None of the above

7. Hydrated Cd(II) complex can be replaced successively by Br^– finally in order to give [CdBr₄]^2-. In this process, it is observed that the fourth equilibrium constant is higher than the third one. The reason behind this is:

1. equilibrium constant for the last step is always the highest.
2. three molecules of H₂O are released during the fourth step.
3. the aqua-Cd(II) species is octahedral
4. an anion(Br^–) will replace a neutral (H₂O) molecules from the coordination sphere.

8. Hydrated Cd(II) complex can be replaced successively by Br^– finally in order to give [CdBr₄]^2-. In this process, it is observed that the fourth equilibrium constant is higher than the third one. The reason behind this is:

1. The equilibrium constant for the last step is always the highest.
2. three molecules of H₂O are released during the fourth step.
3. the aqua-Cd(II) species is octahedral
4. an anion(Br^–) will replace a neutral (H₂O) molecules from the coordination sphere.

9. A dilute solution of KCl was placed between two Pt electrode having a distance of 10.0 cm and a potential difference of 6.0 volt was applied. How much distance will be travelled by K⁺ ions in 2 hour at 25° C? ( Given: Ionic conductivity of K⁺ at infinite dilution is 73.52 S cm² eq^–1. at 25°C).

1. 2.125 cm
2. 1.511 m
3. 3.292 cm
4. 2.512 cm

10. The graph between  and log P gives a straight line with an angle of 45°. If pressure is 0.5 atm and log k = 0.699, calculate the amount of solute adsorbed per g of adsorbent.

1. 1 g/g adsorbent
2. 2.5 g/g adsorbent
3. 1.5 g/g adsorbent
4. 0.25 g/g adsorbent