Relation between the roots of the equation of the Nth degree

By Asakti|Updated : September 9th, 2016

Dear Aspirants,

Today we will see what is the relation between the roots of an equation of the Nth degree.

Let the equation of the nth degree be :

a0xn + a1xn-1 + a2xn-2 + …… + an , where a0, a1, a2, … an are not equal to 0.

Sum of the roots =  (-a1/a0)

Sum of the products of the roots taken two at a time=  (a2/a0)

Sum of the products of the roots taken three at  a time = (-a3/a0)

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Product of the roots =  (-1)n[an/a0]

Example: Find the relation between the different roots of the equation: (2x4 + 10x3 – 8x2 +9)

Solution: As the equation is of degree 4, so the number of roots of the equation are 4. Let the roots be : A, B, C and D.

Sum of the roots, (A+B+C+D) = (-10/2) = -5

Sum of products of roots taken two at a time, (AB + BC + CD+ AC + AD + BD )= (-8/4) = -2

Sum of the products of the roots taken three at a time = 0 (As the coefficient of x is 0)

Products of the roots = (AxBxCxD) = 9/2

Thanks!

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