Dear Aspirants,
Today we will see what is the relation between the roots of an equation of the Nth degree.
Let the equation of the nth degree be :
a0xn + a1xn-1 + a2xn-2 + …… + an , where a0, a1, a2, … an are not equal to 0.
Sum of the roots = (-a1/a0)
Sum of the products of the roots taken two at a time= (a2/a0)
Sum of the products of the roots taken three at a time = (-a3/a0)
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Product of the roots = (-1)n[an/a0]
Example: Find the relation between the different roots of the equation: (2x4 + 10x3 – 8x2 +9)
Solution: As the equation is of degree 4, so the number of roots of the equation are 4. Let the roots be : A, B, C and D.
Sum of the roots, (A+B+C+D) = (-10/2) = -5
Sum of products of roots taken two at a time, (AB + BC + CD+ AC + AD + BD )= (-8/4) = -2
Sum of the products of the roots taken three at a time = 0 (As the coefficient of x is 0)
Products of the roots = (AxBxCxD) = 9/2
Thanks!
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